Oracle SQL：總結HH：MI：SS

Question

我使用以下腳本來總結一個生產訂單的完成和下一個生產訂單的開始之間的持續時間......

select mac.name, par.name name_1, ref.name Fehler, count(*) count,
case when 
    to_char(to_date('01-JAN-2001 00:00:00','DD-MM-YYYY HH24:MI:SS')+(sum(log.time_stamp_to - log.time_stamp_on)),'HH24:MI:SS') 
        > to_char(to_date('01-JAN-2001 00:35:00','DD-MM-YYYY HH24:MI:SS'),'HH24:MI:SS')
    then 
        to_char(to_date('01-JAN-2001 00:35:00','DD-MM-YYYY HH24:MI:SS'),'HH24:MI:SS') 
    else  
        to_char(to_date('01-JAN-2001 00:00:00','DD-MM-YYYY HH24:MI:SS')+(sum(log.time_stamp_to - log.time_stamp_on)),'HH24:MI:SS')
end duration
from mde_logstate log
right outer join mde_refstate ref
    on log.mach_typ = ref.mach_typ
    and log.part_id = ref.part_id
    and log.state_id = ref.state_id
    and ref.name = 'ORDERCHANGE'
right outer join mde_machpart par
    on log.mach_typ = par.mach_typ
    and log.part_id = par.part_id
right outer join mde_mach mac
    on log.mach_typ = mac.mach_typ 
    and log.mach_id = mac.mach_id 
    and mac.name = 'OFFSET PRINTER NO.3'
where log.mach_typ in ('80','82')
and log.time_stamp_on between to_date('01-05-2017 06:00:00','DD-MM-YYYY HH24:MI:SS') and to_date('01-06-2017 06:59:59','DD-MM-YYYY HH24:MI:SS')
and not 
        (select to_char(to_date('01-JAN-2001 00:00:00','DD-MM-YYYY HH24:MI:SS')+(sum(a1.time_stamp_to-a1.time_stamp_on)),'HH24:MI:SS')
            from mde_logstate a1, mde_refstate b, mde_machpart d, mde_mach e1
            where a1.mach_typ = log.mach_typ and a1.mach_typ = b.mach_typ and a1.mach_typ = d.mach_typ and a1.mach_typ = mac.mach_typ and a1.mach_id = e1.mach_id
            and a1.part_id = b.part_id and a1.part_id = d.part_id and a1.state_id = b.state_id and b.name = 'PRODUCTION'
            and a1.time_stamp_on between to_date('01-05-2017 06:00:00','DD-MM-YYYY HH24:MI:SS') and to_date('01-06-2017 06:59:59','DD-MM-YYYY HH24:MI:SS')
            and trunc(log.time_stamp_on) = trunc(a1.time_stamp_on) and e1.short_name = mac.short_name) is null
group by log.time_stamp_on, mac.name, par.name, ref.name, mac.mach_typ, log.mach_typ, mac.short_name

case函數用'00：35：00'替換大於'00：35：00'的'Durations'。 當腳本運行時，我得到以下16行結果。

我想要做的是從組中刪除'a.time_stamp_on'，只留下持續時間的總和（07:26:55），但是當我按功能I從組中刪除'a.time_stamp_on'時得到以下結果;

如何獲得“持續時間”總和？ 我嘗試了以下'sum over partition by'，但我得到一個oracle錯誤（ORA-01722：無效數字）：

sum(case when 
    to_char(to_date('01-JAN-2001 00:00:00','DD-MM-YYYY HH24:MI:SS')+(sum(a.time_stamp_to - a.time_stamp_on)),'HH24:MI:SS') 
        > to_char(to_date('01-JAN-2001 00:35:00','DD-MM-YYYY HH24:MI:SS'),'HH24:MI:SS')
    then 
        to_char(to_date('01-JAN-2001 00:35:00','DD-MM-YYYY HH24:MI:SS'),'HH24:MI:SS') 
    else 
        to_char(to_date('01-JAN-2001 00:00:00','DD-MM-YYYY HH24:MI:SS')+(sum(a.time_stamp_to - a.time_stamp_on)),'HH24:MI:SS')
end) over (partition by e.name)

Answer 1

我會用lead來計算持續時間，見下面的樣本

with orders as
(select 1 as order_num, sysdate-9 as startdate from dual union all
 select 2 as order_num, sysdate-8 as startdate from dual union all
 select 3 as order_num, sysdate-7 as startdate from dual union all
 select 4 as order_num, sysdate-4 as startdate from dual union all
 select 5 as order_num, sysdate-1 as startdate from dual
)
select order_num, startdate, lead(startdate, 1) over (order by startdate) next_order_start
       ,nvl(lead(startdate, 1) over (order by startdate), startdate) - startdate as duration
 from  orders

    ORDER_NUM   STARTDATE   NEXT_ORDER_START    DURATION
1   1   16/06/2017 17:13:53 17/06/2017 17:13:53 1
2   2   17/06/2017 17:13:53 18/06/2017 17:13:53 1
3   3   18/06/2017 17:13:53 21/06/2017 17:13:53 3
4   4   21/06/2017 17:13:53 24/06/2017 17:13:53 3
5   5   24/06/2017 17:13:53     0