[英]Java JCombobox and JButton issue
我目前正在為我的計算機科學課設計一個項目,但遇到了問題。 我有多個按鈕和2個組合框,我希望它們彼此獨立工作。 不幸的是,每當我按下一個按鈕時,它就充當“選擇”按鈕,並激活組合框中當前選擇的任何內容! 我將如何解決這個問題? 我的代碼片段如下
public void actionPerformed(ActionEvent e) {
// Sound Menu
String soundSelect = (String)soundBox.getSelectedItem();
int soundIndex = soundBox.getSelectedIndex();
switch (soundIndex){
case 0:
stopClip(meowSong);
stopClip(meowRemix);
ImageIcon catDel = new ImageIcon(getClass().getResource("tres-quatro.png"));
delEvent.setIcon(catDel);
ImageIcon catAdd = new ImageIcon(getClass().getResource("im-hungry.png"));
addEvent.setIcon(catAdd);
break;
case 1:
stopClip(meowRemix);
playMeow(meowSong);
catDel = new ImageIcon(getClass().getResource("tres-quatro.png"));
delEvent.setIcon(catDel);
catAdd = new ImageIcon(getClass().getResource("im-hungry.png"));
addEvent.setIcon(catAdd);
break;
case 2:
stopClip(meowSong);
playMeow(meowRemix);
ImageIcon thugCat = new ImageIcon(getClass().getResource("tres-quatro-thug.png"));
delEvent.setIcon(thugCat);
ImageIcon hungryThug = new ImageIcon(getClass().getResource("im-hungry-thug.png"));
addEvent.setIcon(hungryThug);
break;
}
// View Menu
String viewSelect = (String)viewTypes.getSelectedItem();
if(e.getActionCommand().equals("ADD EVENT"))
{
playMeow(meowSound);
createEvent();
}else if(e.getActionCommand().equals("DELETE EVENT"))
{
playMeow(meowSound);
deleteEvent();
}else{
panel.remove(displayMessage2);
panel.add(displayMessage);
panel.remove(text);
}
int selection = viewTypes.getSelectedIndex();
switch (selection)
{
case 0: displayMessage.setText("Enter the Sunday of the week you'd like to view! DD/MM");
panel.add(text);
panel.add(enter);
String date = text.getText();
if(e.getActionCommand().equals("Enter")){
weeklyCalendar(calendar.getHashmap(), date);
displayMessage.setText("Select a CATlendar view or you can ADD or DELETE an event!");
panel.remove(text);
panel.remove(enter);
}
break;
case 1: displayMessage.setText("Enter the date you'd like to view! DD/MM");
panel.add(text);
panel.add(enter);
date = text.getText();
if(e.getActionCommand().equals("Enter")){
playMeow(meowSound);
dailyCalendar(calendar.getHashmap(), date);
displayMessage.setText("Select a CATlendar view or you can ADD or DELETE an event!");
panel.remove(text);
panel.remove(enter);
}
break;
case 2: displayMessage.setText("Press Enter to view monthly");
panel.remove(text);
panel.add(enter);
if(e.getActionCommand().equals("Enter")){
monthlyCalendar();
displayMessage.setText("Select a CATlendar view or you can ADD or DELETE an event!");
panel.remove(enter);
}
break;
}
panel.revalidate();
panel.repaint();
SwingUtilities.windowForComponent(panel).pack();
}
每當我按下一個按鈕時,它就充當“選擇”按鈕,並激活組合框中當前選擇的任何內容
嗯,這就是您的ActionListener代碼所要做的。 無論哪個組件生成了ActionEvent,您始終執行switch語句。
為每個組件創建單獨的ActionListener,而不是嘗試為所有組件共享單個ActionListener。 然后,代碼將針對每個組件而特定,並且不需要if語句來確定哪個組件生成了事件。
編輯:
您如何為每個組件設置單獨的actionListener?
您可以創建實現ActionListener接口的內部類
comboBox.addActionListener( new MyComboBoxListener() ); ... class MyComboBoxListener implements ActionListener { @Override public void actionPerformed(ActionEvent e) { // add your code here } }
您可以使用匿名內部類
comboBox.addActionListenener( new ActionListener() { @Override public void actionPerformed(ActionEvent e) { // add your code here } });
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