為什么我的UIImageView替換第二個？

Question

我為兩個不同的UIImageViews有兩個插座，當我選擇第一個時，它將出現在第一個Image View中，但是當我選擇第二個Image時，即使它已連接到第二個ImageView，它也會替換第一個Image View。 這是我的“選擇圖像”按鈕的代碼。

@IBOutlet weak var myImageView1: UIImageView!
@IBOutlet weak var myImageView2: UIImageView!


@IBAction func pickImage1(_ sender: Any) {

    let image = UIImagePickerController()
    image.delegate = self
    image.sourceType = UIImagePickerControllerSourceType.photoLibrary
    image.allowsEditing = false

    self.present(image, animated: true)
}

//Add didFinishPickingMediaWithInfo here
func imagePickerController(_ picker: UIImagePickerController, didFinishPickingMediaWithInfo info: [String : Any]) {
    if let image = info[UIImagePickerControllerOriginalImage] as? UIImage {
        myImageView1.image = image
    }
    else {
        //error
    }
    self.dismiss(animated: true, completion: nil)
}


@IBAction func pickImage2(_ sender: Any) {
    let image2 = UIImagePickerController()
    image2.delegate = self
    image2.sourceType = UIImagePickerControllerSourceType.photoLibrary
    image2.allowsEditing = false

    self.present(image2, animated: true)
}

//Add didFinishPickingMediaWithInfo here
func imagePickerController2(_ picker2: UIImagePickerController, didFinishPickingMediaWithInfo2 info2: [String : Any]) {
    if let image2 = info2[UIImagePickerControllerOriginalImage] as? UIImage {
        myImageView2.image = image2
    }
    else {
        //error
    }
    self.dismiss(animated: true, completion: nil)

}

Answer 1

試試這個代碼。 因此，您需要一個標記來記住單擊哪個圖像視圖，然后在此基礎上設置圖像。

var selected = 1

@IBAction func pickImage1(_ sender: Any) {

    let image = UIImagePickerController()
    image.delegate = self
    image.sourceType = UIImagePickerControllerSourceType.photoLibrary
    image.allowsEditing = false
    selected = 1

    self.present(image, animated: true)
}

//Add didFinishPickingMediaWithInfo here
func imagePickerController(_ picker: UIImagePickerController, didFinishPickingMediaWithInfo info: [String : Any]) {
    if let image = info[UIImagePickerControllerOriginalImage] as? UIImage {
        if selected == 1 {
            myImageView1.image = image
        } else {
            myImageView2.image = image
        }
    }
    else {
        //error
    }
    self.dismiss(animated: true, completion: nil)
}


@IBAction func pickImage2(_ sender: Any) {
    let image2 = UIImagePickerController()
    image2.delegate = self
    image2.sourceType = UIImagePickerControllerSourceType.photoLibrary
    image2.allowsEditing = false
    selected = 2

    self.present(image2, animated: true)
}

向前看，當您擁有多個圖像視圖時，可以使用另一種方法來避免在各處復制代碼。

首先，為每個圖像視圖添加唯一的標簽。 避免使用0，因為默認標記為0。因此，您將看到帶有標記為1至4的圖像視圖。

對所有圖像視圖調用相同的方法，以便通過單擊任意一個圖像來觸發此功能

let tapGestureRecognizer = UITapGestureRecognizer(target: self, action: #selector(imageTapped(tapGestureRecognizer:)))
imageView.addGestureRecognizer(tapGestureRecognizer)

處理程序看起來像這樣

func imageTapped(tapGestureRecognizer: UITapGestureRecognizer)
{
    let image = UIImagePickerController()
    image.delegate = self
    image.sourceType = UIImagePickerControllerSourceType.photoLibrary
    image.allowsEditing = false
    let tappedImage = tapGestureRecognizer.view as! UIImageView
    selected = tappedImage.tag
    self.present(image, animated: true)
}

終於在圖片挑選代表

func imagePickerController(_ picker: UIImagePickerController, didFinishPickingMediaWithInfo info: [String : Any]) {
    if let image = info[UIImagePickerControllerOriginalImage] as? UIImage {
        if let imageView = self.view.viewWithTag(selected) as? UIImageView {
            imageView.image = image
        }
    }
    else {
        //error
    }
    self.dismiss(animated: true, completion: nil)
}

Answer 2

問題是您已經重命名了委托方法。 如果這樣做，該方法將不會被識別或調用。

所選答案的另一個選項是擴展UIImageView並使其遵循UIImagePickerControllerDelegate / UINavigationControllerDelegate 。

extension UIImageView: UIImagePickerControllerDelegate, UINavigationControllerDelegate {

     public func imagePickerController(_ picker: UIImagePickerController, didFinishPickingMediaWithInfo info: [String : Any]) {
          guard let selectedImage = info[UIImagePickerControllerOriginalImage] as? UIImage else {
             //handle error
             return
         }

         image = selectedImage
         picker.presentingViewController?.dismiss(animated: true)
     }

     func presentImagePicker(from viewController: UIViewController) {
         let picker = UIImagePickerController()
         picker.delegate = self
         picker.sourceType = .photoLibrary
         picker.allowsEditing = false

         viewController.present(picker, animated: true)
     }
}

這很好，因為您可以用一行啟動應用程序中任何UIImageView的圖像選擇器，如下所示：

@IBAction func pickImage1(_ sender: UIButton) {
    myImageView1.presentImagePicker(from: self)
}