[英]Openpyxl: How to copy a row after checking if a cell contains specific value
我有一個每周更新數千行的工作表,並且需要在過濾后從該工作表中轉移行。 我正在使用當前代碼查找具有所需值的單元格,然后將整行傳輸到另一張工作表,但是保存文件后,出現“ IndexError:列表索引超出范圍”異常。
我使用的代碼如下:
import openpyxl
wb1 = openpyxl.load_workbook('file1.xlsx')
wb2 = openpyxl.load_workbook('file2.xlsx')
ws1 = wb1.active
ws2 = wb2.active
for row in ws1.iter_rows():
for cell in row:
if cell.value == 'TrueValue':
n = 'A' + str(cell.row) + ':' + ('GH' + str(cell.row))
for row2 in ws1.iter_rows(n):
ws2.append(row2)
wb2.save("file2.xlsx")
我以前用來工作的原始代碼如下,由於大文件導致MS Excel無法打開它們(超過40mb),因此必須對其進行修改。
n = 'A3' + ':' + ('GH'+ str(ws1.max_row))
for row in ws1.iter_rows(n):
ws2.append(row)
謝謝。
我不確定您要做什么,但我懷疑問題是您嵌套了復制循環。
請嘗試以下操作:
row_nr = 1
for row in ws1:
for cell in row:
if cell.value == "TrueValue":
row_nr = cell.row
break
if row_nr > 1:
break
for row in ws1.iter_rows(min_row=row_nr, max_col=190):
ws2.append((cell.value for cell in row))
使用列表來保存特定行的每一列中的項目。 然后將該列表附加到您的ws2 。
...
def iter_rows(ws,n): #produce the list of items in the particular row
for row in ws.iter_rows(n):
yield [cell.value for cell in row]
for row in ws1.iter_rows():
for cell in row:
if cell.value == 'TrueValue':
n = 'A' + str(cell.row) + ':' + ('GH' + str(cell.row))
list_to_append = list(iter_rows(ws1,n))
for items in list_to_append:
ws2.append(items)
問題 :我收到“ IndexError:列表索引超出范圍”異常。
我從
ws1.iter_rows(n)
UserWarning: Using a range string is deprecated. Use ws[range_string]
並來自
ws2.append(row2)
。ValueError: Cells cannot be copied from other worksheets
原因是
row2
確實list of Cell objects
list of Values
而不是list of Values
問題 :...需要在過濾后從此工作表傳輸行
例如,以下操作可以滿足您的要求:
# If you want to Start at Row 2 to append Row Data
# Set Private self._current_row to 1
ws2.cell(row=1, column=1).value = ws2.cell(row=1, column=1).value
# Define min/max Column Range to copy
from openpyxl.utils import range_boundaries
min_col, min_row, max_col, max_row = range_boundaries('A:GH')
# Define Cell Index (0 Based) used to Check Value
check = 0 # == A
for row in ws1.iter_rows():
if row[check].value == 'TrueValue':
# Copy Row Values
# We deal with Tuple Index 0 Based, so min_col must have to be -1
ws2.append((cell.value for cell in row[min_col-1:max_col]))
使用Python測試:3.4.2-openpyxl:2.4.1-LibreOffice:4.3.3.2
我能夠通過我的項目清單解決此問題。
import openpyxl
#load data file
wb1 = openpyxl.load_workbook('original.xlsx')
sheet1 = wb1.active
print("loaded 1st file")
#new template file
wb2 = openpyxl.load_workbook('blank.xlsx')
sheet2 = wb2.active
print("loaded 2nd file")
header = sheet1[1:1] #grab header row
listH =[]
for h in header:
listH.append(h.value)
sheet2.append(listH)
colOfInterest= 11 # this is my col that contains the value I'm checking against
for rowNum in range(2, sheet1.max_row +1): #iterate over each row, starting with 2 to skipping header from original file
if sheet1.cell(row=rowNum, column=colOfInterest).value is not None: #interested in non blank values in column 11
listA = [] # list which will hold my data
row = sheet1[rowNum:rowNum] #creates a tuple of row's data
#print (str(rowNum)) # for debugging to show what rows are copied
for cell in row: # for each cell in the row
listA.append(cell.value) # add each cell's data as an element in the list
if listA[10] == 1: # condition1 I'm checking for by looking up the index in the list
sheet2.append(listA) # appending the sheet2's next available row
elif listA[10] > 1: # condition2 I'm checking for by looking up the index in the list
# do something else and store it in bar
sheet2.append(bar) # appending the sheet2's next available row
print("saving file...")
wb2.save('result.xlsx') # save file
print("Done!")
經過測試:Python 3.7 openpyxl 2.5.4
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