[英]How to select first N elements in hierarchical query (Oracle SQL)
我有以下問題。 oracle12 db中有一個包含數百萬個元素的層次結構。 如何選擇層次結構的前N個對象。 選擇哪個對象都沒有關系,唯一的要求是對象應該具有繼承權。 Rownum過濾器根本不起作用:
SELECT object_id
FROM objects
WHERE rownum < 10
START WITH object_id = 9072243521013844211
CONNECT BY PRIOR object_id = parent_id
我得到以下執行計划:對象選擇后進行過濾。
/*
LEVEL PLAN ROWS COST PREDICATES
*/
1 SELECT STATEMENT (OPTIMIZER=ALL_ROWS) 8 1
2 COUNT
3 FILTER filter(ROWNUM<10)
4 CONNECT BY (WITH FILTERING) access("PARENT_ID"=PRIOR "OBJECT_ID")
5 TABLE ACCESS (BY INDEX ROWID) "OBJECTS"
6 INDEX (UNIQUE SCAN) "XPKOBJECTS" 1 1 access("OBJECT_ID"=9072243521013844211)
5 NESTED LOOPS
6 CONNECT BY PUMP
6 TABLE ACCESS (BY INDEX ROWID BATCHED) "OBJECTS" 8 1
7 INDEX (RANGE SCAN) "XIF25OBJECTS" 8 1 access("PARENT_ID"=PRIOR "OBJECT_ID")
以下示例解決方案應提供一些指導:
with objects as
(select level object_id, decode(level+1, :len+1, null, level+1) parent_id
from dual connect by level<=:len )
SELECT object_id
FROM objects
where level <= :n_objects
START WITH object_id = 1
CONNECT BY PRIOR parent_id = object_id
;
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