如何根據數組元素的屬性值將數組重組為對象？

Question

我有這個數組，（包含“ love” btw的所有定義）：

[
    {
        def: "a strong positive emotion of regard and affection",
        exemple: "hildren need a lot of love",
        class_: "noun"
    },
    {
        def: "any object of warm affection or devotion",
        exemple: "the theater was her first love",
        class_: "noun"
    },
    {
        def: "sexual activities (often including sexual intercourse) between two people",
        exemple: "he has a very complicated love life",
        class_: "noun"
    },


    {
        def: "have a great affection or liking for", 
        exemple: "She loves her boss and works hard for him",
        class_: "verb"
    },
    {
        def: "get pleasure from",
        exemple: "I love cooking",
        class_: "verb"
    },
]

是否可以通過根據<class_>的值對數組元素進行分組，使用Underscore-PHP或PHP Array函數將數組重新構造為對象，如下所示：

{
    noun: [
    {
        def: "a strong positive emotion of regard and affection",
        exemple: "hildren need a lot of love",
        class_: "noun"
    },
    {
        def: "any object of warm affection or devotion",
        exemple: "the theater was her first love",
        class_: "noun"
    },
    {
        def: "sexual activities (often including sexual intercourse) between two people",
        exemple: "he has a very complicated love life",
        class_: "noun"
    },
    ],


    verb: [
    {
        def: "have a great affection or liking for", 
        exemple: "She loves her boss and works hard for him",
        class_: "verb"
    },
    {
        def: "get pleasure from",
        exemple: "I love cooking",
        class_: "verb"
    },
    ]
}

Answer 1

將您的json字符串轉換為分組字符串的算法如下：

• 使用json_decode()函數解碼json字符串以獲取多維數組。
• 遍歷數組以根據需要對數組元素進行分組。
• 最后使用json_encode()函數對數組進行編碼，以獲取所需的json字符串。

因此，您的代碼應如下所示：
（假設$json是您的原始json字符串）

// suppose $json is your original json string
$array = json_decode($json, true);

$resultArr = array();
foreach($array as $arr){
    $resultArr[$arr['class_']][] = $arr;
}

// display the resultant json string
echo json_encode($resultArr);