[英]String indices must be integers - substring
我想獲得一個長度字符串,並進行程序計數,並顯示在輸入的字符串中找到的字母"T"
的總數,但出現以下錯誤。 第13行是這樣的: if string[0,counter] == "T":
有什么建議么?
文件“ python”,第13行,在TypeError中:字符串索引必須為整數
#Variable to hold number of Ts in a string
numTs = 0
#Get a sentence from the user.
string = input("Enter a string: ")
#Count the number of Ts in the string.
for counter in range(0,len(string)):
if string[0,counter] == "T":
numTs = numTs + 1
#Display the number of Ts.
print("That string contains {} instances of the letter T.".format(numTs))
#Count the number of Ts in the string.
for counter in range(0,len(string)):
if string[0,counter] == "T":
numTs = numTs + 1
您的string
索引是一個tuple
: 0, counter
。
相反,您應該只使用索引counter
。
for counter in range(0,len(string)):
if string[counter] == "T":
numTs = numTs + 1
如果您的目標不僅僅是學習如何實現這樣的算法,那么更慣用的方法是使用標准庫的Counter
。
>>> string = 'STack overflow challenge Topic'
>>> from collections import Counter
>>> c = Counter(string)
>>>
>>> c['T']
2
string = input("Enter the string:\n");count = 0
for chars in string:
if chars == "T" or chars == "t":
count = count + 1
print ("Number of T's in the string are:",count)
這將找到給定字符串中的t數
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