[英]Join 2 inner join result into one result
大家我都有問題。 我有兩個獨立運行的查詢。 但是我想將我嘗試過的查詢合並為一個查詢,但是這些查詢不起作用。 我需要加入兩個輸出。
第一個查詢:
SELECT q_internal_table.q_part_id,
q_external_table.q_external_id,
q_external_table.q_external_approve,
q_external_table.q_order_id,
q_internal_table.q_internal_id,
q_internal_table.q_internal_approve
FROM (SELECT parts.id AS q_part_id,
parts.order_id AS q_order_id,
external_reports.id AS q_external_id,
external_reports.approved AS q_external_approve
FROM parts
INNER JOIN external_reports
ON( parts.id = external_reports.part_id ))
q_external_table
INNER JOIN (SELECT parts.id AS q_part_id,
internal_reports.id AS q_internal_id,
internal_reports.approved AS q_internal_approve
FROM parts
INNER JOIN internal_reports
ON( parts.id = internal_reports.part_id ))
q_internal_table
ON( q_external_table.q_part_id = q_internal_table.q_part_id )
WHERE ( q_external_table.q_external_approve = 'Y'
OR q_internal_table.q_internal_approve = 'Y' )
第二個查詢:
SELECT q_five_internal_table.q_five_part_id,
q_five_internal_table.q_five_internal_id,
q_five_internal_table.q_five_internal_approve,
q_five_external_table.q_five_external_id,
q_five_external_table.q_five_external_approve,
q_five_external_table.q_five_order_id
FROM (SELECT parts.id AS q_five_part_id,
parts.order_id AS q_five_order_id,
five_way_external_reports.id AS q_five_external_id,
five_way_external_reports.approved AS q_five_external_approve
FROM parts
INNER JOIN five_way_external_reports
ON( parts.id = five_way_external_reports.part_id ))
q_five_external_table
INNER JOIN (SELECT parts.id AS q_five_part_id,
five_way_internal_reports.id AS q_five_internal_id,
five_way_internal_reports.approved AS q_five_internal_approve
FROM parts
INNER JOIN five_way_internal_reports
ON( parts.id = five_way_internal_reports.part_id ))
q_five_internal_table
ON( q_five_external_table.q_five_part_id = q_five_internal_table.q_five_part_id )
WHERE ( q_five_external_table.q_five_external_approve = 'Y'
OR q_five_internal_table.q_five_internal_approve = 'Y' )
我已經嘗試過此查詢:
SELECT q_internal_external_table.*,
q_five_internal_external_table.*
FROM (SELECT q_internal_table.q_part_id,
q_external_table.q_external_id,
q_external_table.q_external_approve,
q_external_table.q_order_id,
q_internal_table.q_internal_id,
q_internal_table.q_internal_approve
FROM (SELECT parts.id AS q_part_id,
parts.order_id AS q_order_id,
external_reports.id AS q_external_id,
external_reports.approved AS q_external_approve
FROM parts
INNER JOIN external_reports
ON( parts.id = external_reports.part_id ))
q_external_table
INNER JOIN (SELECT parts.id AS q_part_id,
internal_reports.id AS q_internal_id,
internal_reports.approved AS q_internal_approve
FROM parts
INNER JOIN internal_reports
ON( parts.id = internal_reports.part_id ))
q_internal_table
ON( q_external_table.q_part_id = q_internal_table.q_part_id )
WHERE ( q_external_table.q_external_approve = 'Y'
OR q_internal_table.q_internal_approve = 'Y' ))
q_internal_external_table
INNER JOIN (SELECT q_five_internal_table.q_five_part_id,
q_five_internal_table.q_five_internal_id,
q_five_internal_table.q_five_internal_approve,
q_five_external_table.q_five_order_id,
q_five_external_table.q_five_external_id,
q_five_external_table.q_five_external_approve
FROM (SELECT parts.id AS q_five_part_id,
parts.order_id AS
q_five_order_id
,
five_way_external_reports.id AS
q_five_external_id,
five_way_external_reports.approved AS
q_five_external_approve
FROM parts
INNER JOIN five_way_external_reports
ON( parts.id = five_way_external_reports.part_id ))
q_five_external_table
INNER JOIN (SELECT parts.id AS q_five_part_id,
five_way_internal_reports.id AS
q_five_internal_id,
five_way_internal_reports.approved AS
q_five_internal_approve
FROM parts
INNER JOIN five_way_internal_reports
ON( parts.id = five_way_internal_reports.part_id ))
q_five_internal_table
ON ( q_five_external_table.q_five_part_id =
q_five_internal_table.q_five_part_id )
WHERE ( q_five_external_table.q_five_external_approve = 'Y'
OR q_five_internal_table.q_five_internal_approve = 'Y' ))
q_five_internal_external_table
ON ( q_internal_external_table.q_part_id =
q_five_internal_external_table.q_five_part_id )
查詢結果:- 在此查詢中有三個結果。 但是我希望第一個查詢結果中有7個結果。 這三個答案已經在第一個查詢結果中。 我也需要休息4 我認為問題出在ON q_internal_external_table.q_part_id = q_five_internal_external_table.q_five_part_id
。 但是不知道如何解決。
請幫我。 提前致謝。
您需要的是UNION
。
兩個查詢都需要具有相同數量的列和類型。 在您的情況下,您需要更改所選列的順序以使成為UNION
。
應該是這樣的:
SELECT q_internal_table.q_part_id,
q_external_table.q_external_id,
q_external_table.q_external_approve,
q_external_table.q_order_id,
q_internal_table.q_internal_id,
q_internal_table.q_internal_approve
FROM (SELECT parts.id AS q_part_id,
parts.order_id AS q_order_id,
external_reports.id AS q_external_id,
external_reports.approved AS q_external_approve
FROM parts
INNER JOIN external_reports
ON( parts.id = external_reports.part_id ))
q_external_table
INNER JOIN (SELECT parts.id AS q_part_id,
internal_reports.id AS q_internal_id,
internal_reports.approved AS q_internal_approve
FROM parts
INNER JOIN internal_reports
ON( parts.id = internal_reports.part_id ))
q_internal_table
ON( q_external_table.q_part_id = q_internal_table.q_part_id )
WHERE ( q_external_table.q_external_approve = 'Y'
OR q_internal_table.q_internal_approve = 'Y' )
UNION ALL
SELECT q_five_internal_table.q_five_part_id,
q_five_external_table.q_five_external_id,
q_five_external_table.q_five_external_approve,
q_five_external_table.q_five_order_id,
q_five_internal_table.q_five_internal_id,
q_five_internal_table.q_five_internal_approve
FROM (SELECT parts.id AS q_five_part_id,
parts.order_id AS q_five_order_id,
five_way_external_reports.id AS q_five_external_id,
five_way_external_reports.approved AS q_five_external_approve
FROM parts
INNER JOIN five_way_external_reports
ON( parts.id = five_way_external_reports.part_id ))
q_five_external_table
INNER JOIN (SELECT parts.id AS q_five_part_id,
five_way_internal_reports.id AS q_five_internal_id,
five_way_internal_reports.approved AS q_five_internal_approve
FROM parts
INNER JOIN five_way_internal_reports
ON( parts.id = five_way_internal_reports.part_id ))
q_five_internal_table
ON( q_five_external_table.q_five_part_id = q_five_internal_table.q_five_part_id )
WHERE ( q_five_external_table.q_five_external_approve = 'Y'
OR q_five_internal_table.q_five_internal_approve = 'Y' )
注意,我已經更改了第二個查詢中列的順序以匹配第一個查詢的類型。
如果我們假設查詢的最終目標是在下表中找到parts.id,則更新后的查詢似乎正確(理論上):external_reports,internal_reports,five_way_external_reports,five_way_internal_reports
合並查詢1和查詢2的行時將使用並集。
但是,如果嘗試查找匹配的列(join子句),則將使用JOIN而不是UNION。
另外,請嘗試在查詢中使用EXPLAIN和EXPLAIN EXTENDED前綴以了解查詢計划。
特別感謝@ dnoeth。 好人。
修改后的SQL是
select q_internal_external_table.*,q_five_internal_external_table.* from
(select q_internal_table.q_part_id,
q_external_table.q_external_id,q_external_table.q_external_approve,
q_external_table.q_order_id,q_internal_table.q_internal_id,
q_internal_table.q_internal_approve from(SELECT parts.id as
q_part_id,parts.order_id as q_order_id,external_reports.id as
q_external_id,external_reports.approved as q_external_approve from parts
LEFT join external_reports on(parts.id=external_reports.part_id))
q_external_table LEFT join (SELECT parts.id as q_part_id,internal_reports.id
as q_internal_id,internal_reports.approved as q_internal_approve from parts
LEFT join internal_reports on(parts.id=internal_reports.part_id))
q_internal_table on(q_external_table.q_part_id=q_internal_table.q_part_id)
where (q_external_table.q_external_approve='Y' or
q_internal_table.q_internal_approve='Y')) q_internal_external_table LEFT
join (select q_five_internal_table.q_five_part_id,
q_five_internal_table.q_five_internal_id,
q_five_internal_table.q_five_internal_approve,
q_five_external_table.q_five_order_id,
q_five_external_table.q_five_external_id,
q_five_external_table.q_five_external_approve from (SELECT parts.id as
q_five_part_id,parts.order_id as q_five_order_id,
five_way_external_reports.id as q_five_external_id,
five_way_external_reports.approved as q_five_external_approve from parts
LEFT join five_way_external_reports on(parts.id=
five_way_external_reports.part_id)) q_five_external_table LEFT join (SELECT
parts.id as q_five_part_id,five_way_internal_reports.id as
q_five_internal_id,five_way_internal_reports.approved as
q_five_internal_approve from parts LEFT join five_way_internal_reports
on(parts.id=five_way_internal_reports.part_id)) q_five_internal_table on
(q_five_external_table.q_five_part_id=q_five_internal_table.q_five_part_id)
where (q_five_external_table.q_five_external_approve='Y' or
q_five_internal_table.q_five_internal_approve='Y'))
q_five_internal_external_table on (q_internal_external_table.q_part_id
=q_five_internal_external_table.q_five_part_id)
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.