在python中存儲一個隨機生成的數字，可以隨時調用

Question

我想要做的是讓 Python 生成一個介於 1 和 6 之間的數字，然后將 6 添加到我要做的那個數字並為我提供結果，但是我似乎無法弄清楚如何制作可以調用該值，因此它可以在游戲過程中上下波動，這是我目前所擁有的：

import random
import time
Name = input("Before we get started lets get your character created, tell me what is your name?") 
print()
print ("Welcome ",Name," to the adventure of a lifetime. The next thing you will need to do is sort out your character stats. This will require dice rolls which we will do within the game.")
print()

def skillroll():
    skillroll=""

    while skillroll !="Y" and skillroll != "N":
        skillroll = input("First we need to roll for your skill, would you like me to roll? Y/N")

        if skillroll=="Y":
            print("Rolling the dice..")
            skill=random.randint(1,6)
            time.sleep(2)
            print("I rolled a", skill, " I will now add 6 to this so your skill is", skill+6)
            skill=skill+6
            print()

    return skillroll

skillroll()

我只是看不出如何得出最終答案，以便我可以在玩游戲時使用它。

我的一個朋友發給我這個幫助https://github.com/protocol7/python-koans/blob/master/python%202/koans/about_classes.py

但我只是看不出這有什么關系，我在 Stackoverflow 上找到的每個答案都是針對不同語言的。

Answer 1

只需使用：

import random
random.randrange(1, 7)

得到 1 到 6 之間的任何數字。

您的代碼變為：

import random
import time

def skillroll():
    skillroll=""
    while skillroll !="Y" and skillroll != "N":
        skillroll = input("First we need to roll for your skill, would you like me to roll? Y/N")
        if skillroll=="Y":
            print("Rolling the dice..")
            skill = random.randrange(1, 7)
            time.sleep(2)
            print("I rolled a ", skill, ". I will now add 6 to this so your skill is", skill+6, "\n")
            skill=skill+6
            return skillroll # What if N??

Name = input("Before we get started lets get your character created, tell me 
what is your name?") 
print ("\nWelcome ",Name," to the adventure of a lifetime. The next thing you 
will need to do is sort out your character stats. This will require dice 
rolls which we will do within the game.\n")
skillroll()