如何將選擇中的內部查詢轉換為雄辯的laravel 5.4

Question

我有這樣的查詢。

select *,
case l.user_type 
when '0' then 
(select CONCAT(first_name,'',last_name) from users where id=l.user_id) 
when '1' then 
(select party_name from tbl_partys where id=l.user_id) 
end as user_name 
from tbl_leased_comm l 
where l.user_id=$party and l.user_id=$user_id 
order by l.updated_at desc

如何將此查詢轉換為laravel查詢對任何人都有幫助...

Answer 1

是的，對我有用

如，

DB::table('tbl_leased_comm')
            ->select(["*",
                  DB::raw("case tbl_leased_comm.user_type when '0' then (select CONCAT(first_name,'',last_name) from users where id=tbl_leased_comm.user_id) when '1' then (select party_name from tbl_partys where id=tbl_leased_comm.user_id) end as user_name")])
            ->where('tbl_leased_comm.user_id','=',$party )
            ->where('tbl_leased_comm.user_id','=',$user_id)
            ->orderBy('tbl_leased_comm.updated_at', 'desc')
            ->get();

非常感謝..

參考鏈接： 將mysql查詢邏輯轉換為Laravel查詢生成器