使用Laravel Eloquent中另一個表的ID顯示表的名稱

Question

拜托，我的控制器中有一個功能。 我想查詢庫存表以選擇product_id的列表， select后，它應該轉到產品表以向用戶顯示產品的NAME ，而不是product_id 。

public function getStockList()
{
    $stock = DB::table("stocks")->pluck("product_id","product_id")->all();
    $products = DB::table("products")->pluck("name")->where('id', $stock);
    return view('shop.shop')->with(['stocks' => $stocks, 
    'stock' => $stock, 'products' => $products]);
}

我的PHP刀片有

{!! Form::select
(
    'stock',
    ['' => 'Select'] +$stock,'',
    array(
        'class'=>'form-control',
        'id'=>'country',
        'style'=>'width:350px;'
        )
)!!}

{!! Form::select
(
    'product_id',
    [''=>'Select Supplier'] + $products, null, 
    ['class'=>'form-control']
)!!}

基本上，我不希望product_id顯示給用戶，而是顯示產品名稱。

Answer 1

嘗試這個

public function getStockList()
{
    $stock = DB::table("stocks")->pluck("product_id");
    $products = DB::table("products")->whereIn('id', $stock)->pluck("name","id");
    return view('shop.shop')->with([
        'stocks'   => $stocks,
        'stock'    => $stock,
        'products' => $products
    ]);
}

用以下內容替換您的產品列表選擇框

{!! Form::select('product_id',$products,null, ['class'=>'form-control','placeholder'=>'Select Products'])!!}

Answer 2

你需要數組來傳遞表單

/* $product_array = ['1' => 'product 1',  '2' => 'product 2', '3' => 'product 3']; */

所以在你的控制器中

$product_array = []
  foreach($products as $product){
    $product_array[$product->id] = $product->name;
  }

return view('shop.shop')->with(['stocks' => $stocks, 
'stock' => $stock, 'products' => $products , 'product_array'=>$product_array]);

在您看來

{{!! Form::select('product_id', $product_array , null, ['class'=>'form-control'])!! }}

希望這會有所幫助。