如何使用Java Split在正則表達式中匹配整個單詞

Question

我正在嘗試根據我的要求拆分單詞。 我想根據整個單詞進行拆分。

如下所示的示例，

Actual        -       Expecting

10% to 20%    -     10 to 20%
10% and 60%   -     10 and 60%
5 % to 10 %   -     5 to 10% 
25 to 125     -    no need to change

我的示例字符串

 String str = "Zimowski, M. F., Muraki, E., Mislevy, R 10% to 25% J., & Btock, R. D. (1996). BILOG-MG: [mMultiple 10% and 25%-group IRT]( analysis and test maintenance for binary items. Chicago, IL: 5% Scientific) Software).[AQ: “Zimowski,10 % to 25% Muraki, Mislevy, & Bock, 1996�is not cited 10 to 25% in text. Please indicate where a citation 10 and 25% should appear or allow us to delete the reference.]";

我的預期結果

String result = "Zimowski, M. F., Muraki, E., Mislevy, R 10 to 25% J., & Btock, R. D. (1996). BILOG-MG: [mMultiple 10 and 25%-group IRT]( analysis and test maintenance for binary items. Chicago, IL: 5% Scientific) Software).[AQ: “Zimowski,10 to 25% Muraki, Mislevy, & Bock, 1996�is not cited 10 to 25% in text. Please indicate where a citation 10 and 25% should appear or allow us to delete the reference.]";

我嘗試在出現“ and”，“ to”時拆分字符串。 但顯然還沒有完成（根據要求）。

因此，請提出建議並讓我知道。

Answer 1

嘗試這個：

str = str.replaceAll("(\\\\d\\\\d?\\\\d?\\\\s?)(%)(\\\\s)(and|to)(\\\\s\\\\d\\\\d?\\\\d?\\\\s?)","$1$3$4$5");

Answer 2

看一下java.util.regex.Matcher類，特別是方法appendReplacement。

import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class SanJose { 
    public static void main(String[] args) {
        String myString = "10% to 20% aaa 10% and 60% bbb 5 % to 10 % ddd 25 to 125";
        Pattern p = Pattern.compile("\\d+\\s*%\\s+(to|and)");
        Matcher m = p.matcher(myString);
        StringBuffer sb = new StringBuffer();
        while (m.find()) {
            m.appendReplacement(sb, m.group().replace("%", ""));
        }
        m.appendTail(sb);
        System.out.println(sb.toString());
    }
}