[英]SQL: 3 self-joins and then join them together
我有2個表以特定方式加入。 我認為我的查詢是正確的,但不確定。
select t1.userID, t3.Answer Unit, t5.Answer Demo
FROM
table1 t1
inner join (select * from table2) t3 ON t1.userID = t3.userID
inner join (select * from table2) t5 ON t1.userID = t5.userID
where
NOT EXISTS (SELECT * FROM table1 t2 WHERE t2.userID = t1.userID AND t2.date > t1.date)
and NOT EXISTS (SELECT * FROM table2 t4 WHERE t4.userID = t3.userID and t4.counter > t3.counter)
and NOT EXISTS (SELECT * FROM table2 t6 WHERE t6.userID = t5.userID and t6.counter > t5.counter)
and t1.date_submitted >'1/1/2009'
and t3.question = Unit
and t5.question = Demo
order by
t1.userID
從表1我想要日期> 1/1/2009的不同的userID
table1
userID Date
1 1/2/2009
1 1/2/2009
2 1/2/2009
3 1/2/2009
4 1/1/2008
所以我想要的結果來自table1應該是這樣的:
userID
1
2
3
然后,我想在userID和table2上加入它,如下所示:
table2
userID question answer counter
1 Unit A 1
1 Demo x 1
1 Prod 100 1
2 Unit B 1
2 Demo Y 1
3 Prod 100 1
4 Unit A 1
1 Unit B 2
1 Demo x 2
1 Prod 100 2
2 Unit B 2
2 Demo Z 2
3 Prod 100 2
4 Unit A 2
我想將table1與table2結合在一起,結果如下:
userID Unit Demo
1 B X
2 B Z
換一種說法,
從表2中選擇不同的用戶ID,其中問題=最高計數器的單位
接着
從table2中選擇不同的用戶ID,其中問題=最高計數器的演示。
我認為我要做的是3個自我聯接,然后將這3個聯接在一起。
你認為對嗎?
SELECT du.userID, unit.answer, demo.answer
FROM (
SELECT DISTINCT userID
FROM table1
WHERE date > '1/1/2009'
) du
LEFT JOIN
table2 unit
ON (userID, question, counter) IN
(
SELECT du.userID, 'Unit', MAX(counter)
FROM table2 td
WHERE userID = du.userID
AND question = 'Unit'
)
LEFT JOIN
table2 demo
ON (userID, question, counter) IN
(
SELECT du.userID, 'Demo', MAX(counter)
FROM table2 td
WHERE userID = du.userID
AND question = 'Demo'
)
在table2 (userID, question, counter)
上有一個索引table2 (userID, question, counter)
將大大改善此查詢。
自從您提到SQL Server 2005
以來,以下內容將變得更加容易和高效:
SELECT du.userID,
(
SELECT TOP 1 answer
FROM table2 ti
WHERE ti.user = du.userID
AND ti.question = 'Unit'
ORDER BY
counter DESC
) AS unit_answer,
(
SELECT TOP 1 answer
FROM table2 ti
WHERE ti.user = du.userID
AND ti.question = 'Demo'
ORDER BY
counter DESC
) AS demo_answer
FROM (
SELECT DISTINCT userID
WHERE date > '1/1/2009'
FROM table1
) du
匯總:
SELECT answer, COUNT(*)
FROM (
SELECT DISTINCT userID
FROM table1
WHERE date > '1/1/2009'
) du
JOIN table2 t2
ON t2.userID = du.userID
AND t2.question = 'Unit'
GROUP BY
answer
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