如何從列中獲取最高的5個值？

Question

我有帶name和no_of_sell列的產品表。.我想從產品表中獲得基於no_of_sell列的最高5個售出產品。 如何與查詢生成器一起使用？

  $propular_products =  DB::table('users')
            ->join('products','products.auth_id','users.id')
            ->select('products.*')   
            ->orderBy('products.no_of_sell', 'desc')              
            ->where('products.status','=','1') 
            ->paginate(5);

假設products表：

name no_of_sell
 x     6
 y     9
 z     10
 t     23
 u     3
 h     11
 r      5

我想找到

products list of 5 max no_of_sell ie, x y z t h 

Answer 1

因此，如果我在列中正確理解它，則no_of_sell是一個整數。 我應該這樣寫：

$best_sell = DB::table('products')
             ->orderBy('no_of_sell', 'desc')
             ->limit(5)
             ->where('products.status','=','1') 
             ->paginate(4)
             ->get(); 

https://laravel.com/docs/5.4/queries#retrieving-results https://laravel.com/docs/5.4/queries#ordering-grouping-limit-and-offset

Answer 2

$best_sell = DB::table('products')
         ->select('no_of_sell')   
         ->where('products.status','=','1')                       
         ->orderBy('no_of_sell', 'desc')
         ->paginate(4);

Answer 3

$best_sell = DB::table('products')
        ->select() // your selection criteria 
        ->where('products.status','=','1') 
        ->take(5)->get();