[英]How to sum two subqueries count in third variable mysql query?
我正在嘗試匯總喜歡和評論的總數,但結果始終為零(0),因為我已經實施了大部分發現但沒有成功的解決方案,請幫助我解決此問題。
SELECT DISTINCT id,name,picture,
(SELECT COUNT(id) from likes) as likes,
(SELECT COUNT(id) from comments) as comments,
(likes+comments) as total
From users
您不能在定義它們的同一SELECT
中使用列別名。 我建議在FROM
子句中這樣做:
SELECT DISTINCT u.id, u.name, u.picture, l.likes, c.comments,
(l.likes + c.comments) as total
FROM users u CROSS JOIN
(SELECT COUNT(id) as likes FROM likes) l CROSS JOIN
(SELECT COUNT(id) as comments FROM comments) c;
大概u.id
是唯一的。 如果是這樣,則應刪除SELECT DISTINCT
。 它只會對性能產生不利影響。
你可以這樣嘗試
SELECT DISTINCT id,name,picture,
(SELECT COUNT(id) from likes) as likes,
(SELECT COUNT(id) from comments) as comments,
(SELECT COUNT(id) from likes)+(SELECT COUNT(id) from comments) as total
From users
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