是否有使用yii2交叉連接的正確方法？

Question

我正在查詢activedataprovider，將其用於搜索目的。 我需要使用交叉聯接。 我使用了joinWith，但是它抱怨倉庫模型與產品沒有關系。 這是產品。 因為這是交叉聯接，所以在這附近有什么工作可以避免觸發關系嗎？

其他說明：在基於倉庫的原始模型中，諸如product_id，product.category等某些屬性不存在。 如果我僅添加公共屬性/屬性變量還是需要變通解決方案，它會即時運行嗎？

public function search($params)
    {               
        $query = Warehouse::find()->joinWith('product')
                ->select(['product_id' => 'product.id','warehouse.warehouse', 'product.category', 'product.product', 'min_stock' => 'coalesce(critical.min_stock, -1)'])
                ->leftJoin('critical', 'critical.product_id = product.id AND critical.warehouse_id = warehouse.id')
                ->where(['warehouse.id' => $this->_id]);

        $this->load($params);

        $dataProvider = new ActiveDataProvider([
            'query' => $query,
        ]);        

        if (!$this->validate()) {
            // uncomment the following line if you do not want to return any records when validation fails
            // $query->where('0=1');
            return $dataProvider;
        }

        $query->andFilterWhere(['category' => $this->category]);
        $query->andFilterWhere(['like', 'product', $this->product]);        

        return $dataProvider;
    }

Answer 1

對於所有難以（或不可能）使用yii2 activeRecord或activeQuery功能構建的查詢，可以使用findBySql

$sql = "select 
          product.id as id
          , warehouse.warehouse as warehouse 
          , product.category as category
          , product.product as product
          , coalesce(critical.min_stock, -1) as min_stock 
          from Warehouse 
          cross join product  
          left join critical on ritical.product_id = product.id AND critical.warehouse_id = warehouse.id
          where warehouse.id' = " . $this->_id  

 $model =  Warehouse::findBySql($sql );

Answer 2

將查詢記錄獲取為數組，因此您無需定義關系

public function search($params)
    {               
        $query = Warehouse::find()->joinWith('product')
                ->select(['product_id' => 'product.id','warehouse.warehouse', 'product.category', 'product.product', 'min_stock' => 'coalesce(critical.min_stock, -1)'])
                ->leftJoin('critical', 'critical.product_id = product.id AND critical.warehouse_id = warehouse.id')
                ->where(['warehouse.id' => $this->_id]);

        $query = Warehouse::find()
                ->select('product.id as id,warehouse.warehouse as warehouse, product.category as category, product.product as product, coalesce(critical.min_stock, -1) as min_stock ')
                ->leftJoin('product', 'warehouse.product_id = product.id')
                ->leftJoin('critical', 'critical.product_id = product.id')
                ->where(['warehouse.id' => $this->_id]);
                ->andWhere('critical.warehouse_id = warehouse.id')
                ->asArray();

        $this->load($params);

        $dataProvider = new ActiveDataProvider([
            'query' => $query,
        ]);        

        if (!$this->validate()) {
            // uncomment the following line if you do not want to return any records when validation fails
            // $query->where('0=1');
            return $dataProvider;
        }

        $query->andFilterWhere(['category' => $this->category]);
        $query->andFilterWhere(['like', 'product', $this->product]);        

        return $dataProvider;
    }

現在，您將獲得記錄作為數組而不是對象。

第二種方法是，使用hasOne()或hasMany()在模型中定義倉庫與產品之間的關系

Answer 3

-> joinWith（'product'，true，'交叉連接'）

public function getProduct()
{
    return $this->hasOne(Product::className(), []);
}