[英]Data is not inserting to database but retrieving is working fine using PHP and Ajax?
在向您提出我的問題之前,我想澄清一下,我只是Ajax和Jquery的新秀,因此,如果懷疑很小或小菜一碟,請饒恕我,對此深表歉意。
我正在嘗試使用Ajax和PHP為我的電子商務創建評論系統。 問題是,數據沒有插入數據庫中,但是如果我將數據手動插入數據庫中,則它可以完美顯示在我的站點中。我認為變量review或user_review出了點問題,但找不到是的。所以,請您告訴我我做錯了哪里。
<div role="tabpanel" class="tab-pane" id="reviews">
<h4>Write your Review</h4>
<form action="" method="post" onsubmit="return post();">
<textarea id="review" class="reviewbox" placeholder="Write Your Review Here....."></textarea>
<button type="submit" class="btn">Submit</button>
</form>
<div id="all_reviews">
<?php
$query = $pdo->prepare("SELECT * FROM reviews WHERE product_id=?");
$query -> bindValue(1, $id);
$query->execute();
while ($row = $query->fetch(PDO::FETCH_ASSOC))
{
$name = $row['user_name'];
$text = $row['review_text'];
$time = $row['post_time'];
?>
<h5>By <?php echo $name; ?></h5>
<p><i>posted on <?php echo $time; ?></i></p>
<p>
<?php echo $text; ?>
</p>
<hr>
<?php
}
?>
</div>
<script type="text/javascript" src="jquery.js">
< script type = "text/javascript" >
function post() {
var review = document.getElementById("review").value;
if (review) {
$.ajax({
type: 'POST',
url: 'post_reviews.php',
data: {
user_review: review
},
success: function(response) {
document.getElementById("all_reviews").innerHTML = response + document.getElementById("all_reviews").innerHTML;
document.getElementById("review").value = "";
}
});
}
return false;
}
</script>
</div>
這是我的post_reviews.php
:
<?php
session_start();
require('includes/product.php');
require('includes/connect.php');
$product = new Product;
if(isset ($_GET['id'])) {
$id = $_GET['id'];
$data = $product -> fetch_data($id);
if(isset($_POST['user_review'])){
$review=$_POST['user_review'];
if (isset($_SESSION['logged_in'])) {
$query = $pdo -> prepare("INSERT INTO reviews(product_id,user_name,review_text) VALUES (?,?,?)");
$query -> bindValue(1, $id);
$query -> bindValue(2, $_SESSION['name']);
$query -> bindValue(3,$review);
$query ->execute();
}
else{
$review_msg="Please login to post your review";
}
$query = $pdo->prepare("SELECT * FROM reviews WHERE product_id=?");
$query -> bindValue(1, $id);
$query->execute();
while ($row = $query->fetch(PDO::FETCH_ASSOC)){
$name = $row['user_name'];
$text = $row['review_text'];
$time = $row['post_time'];
?>
<?php if(isset($review_msg)){ ?>
<small style = "color : #aa0000"; ><?php echo $review_msg ?></small>
<br><br>
<?php } ?>
<h5>By <?php echo $name; ?></h5>
<p><i>posted on <?php echo $time; ?></i></p>
<p><?php echo $text; ?></p>
<hr>
<?php
}
}
exit;
}
?>
您沒有關閉腳本代碼,這是一個錯誤
<script type="text/javascript" src="jquery.js">
至
<script type="text/javascript" src="jquery.js"></script>
這就是您的ajax無法正常工作的原因。
首先檢查您的ajax是否正常運行
var review = document.getElementById(“ review”)。value;
$.ajax({
type: "POST",
url: "post_reviews.php",
data: review,
cache: false,
dataType: 'json',
success: function(response){
document.getElementById("all_reviews").innerHTML = response + document.getElementById("all_reviews").innerHTML;
document.getElementById("review").value = "";
}
});
return false;
現在我明白了。 您正在提交表格。
<form action="" method="post" onsubmit="return post();">
<textarea id="review" class="reviewbox" placeholder="Write Your Review
Here....."></textarea>
<button type="submit" class="btn">Submit</button>
</form>
嘗試以此替換您的表單:
<form action="" method="post">
<textarea id="review" class="reviewbox" placeholder="Write Your Review
Here....."></textarea>
<button type="button" onclick="post()" class="btn">Submit</button>
</form>
如果按鈕類型為“按鈕”,則不會提交表單。 現在單擊它即可調用您的函數並執行ajax調用。
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