![](/img/trans.png)
[英]how to connect online mysql database server from local wamp server using php?
[英]Can't connect Android application to MySQL database using WAMP as local server
我正在嘗試創建一個簡單的登錄到我的Android應用程序,以按照以下教程將用戶輸入與數據庫數據進行比較:
我將WAMP用作本地服務器只是為了測試是否可以建立連接。 我在以下目錄中放置了兩個名為config.inc.php和login.inc.php的 PHP文件: C:\\ wamp64 \\ www \\ DUFT ,它們看起來像這樣:
config.inc.php文件
<?php $servername = "localhost:80";
$username = "root";
$password = "root";
$dbname = "duft";
try {
$conn = new PDO("mysql:host=$servername;dbname=$dbname", $username, $password);
$conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
}
catch(PDOException $e)
{
die("OOPs something went wrong");
}
?>
login.inc.php
<?php
include 'config.inc.php';
// Check whether username or password is set from android
if(isset($_POST['username']) && isset($_POST['password']))
{
// Innitialize Variable
$result='';
$username = $_POST['username'];
$password = $_POST['password'];
// Query database for row exist or not
$sql = 'SELECT * FROM tbl_login WHERE email = :username AND adgangskode = :password';
$stmt = $conn->prepare($sql);
$stmt->bindParam(':username', $username, PDO::PARAM_STR);
$stmt->bindParam(':password', $password, PDO::PARAM_STR);
$stmt->execute();
if($stmt->rowCount())
{
$result="true";
}
elseif(!$stmt->rowCount())
{
$result="false";
}
// send result back to android
echo $result;
}?>
然后,有了LoginActivity類,在其中使用AsyncTask在后台建立與數據庫的連接。 在onPostExecute()方法中,如果用戶輸入匹配數據庫中的內容,則嘗試啟動新活動。 但是我一直從PHP文件中收到此錯誤:
Call Stack#TimeMemoryFunctionLocation10.0042244400{main}( )...\\login.inc.php : 020.0043245592http://www.php.net/PDO.construct' target='_new'>__construct( )...\\login.inc.php : 10( ! ) Warning: PDO::__construct(): Error while reading greeting packet. (!)警告:PDO :: __ construct():MySQL服務器已在第行的C:\\ wamp64 \\ www \\ DUFT \\ login.inc.php中消失,調用Stack#TimeMemoryFunctionLocation10.0042244400 {main}()... \\ login.inc.php : 020.0043245592http://www.php.net/PDO.construct'target ='_ new'> __ construct()... \\ login.inc.php : 10(!)警告:PDO :: __ construct ():讀取問候數據包時出錯。 Call Stack#TimeMemoryFunctionLocation10.0042244400{main}( )...\\login.inc.php : 020.0043245592http://www.php.net/PDO.construct' target='_new'>__construct( )...\\login.inc.php : 10OOPs something went wrong 第行的C:\\ wamp64 \\ www \\ DUFT \\ login.inc.php中的PID = 9636調用Stack#TimeMemoryFunctionLocation10.0042244400 {main}()... \\ login.inc.php : 020.0043245592http://www.php .net / PDO.construct'target ='_ new'> __ construct()... \\ login.inc.php : 10糟糕
這就是我的logcat所說的:
我的LoginActivity Java類如下所示:
public class LoginActivity extends AppCompatActivity{
//NYT
// CONNECTION_TIMEOUT and READ_TIMEOUT are in milliseconds
public static final int CONNECTION_TIMEOUT=2000000000;
public static final int READ_TIMEOUT=2000000000;
private EditText etEmail;
private EditText etPassword;
//NYT
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_login);
//NYT
// Get Reference to variables
etEmail = (EditText) findViewById(R.id.eMail);
etPassword = (EditText) findViewById(R.id.password);
//NYT
TextView klikHer = (TextView) findViewById(R.id.klikHer);
klikHer.setPaintFlags(klikHer.getPaintFlags() | Paint.UNDERLINE_TEXT_FLAG);
Button login = (Button) findViewById(R.id.signIn);
login.setOnClickListener(new View.OnClickListener() {
public void onClick(View v) {
//Intent intent = new Intent(LoginActivity.this, MenuScreen.class);
//startActivity(intent);
//NYT
// Get text from email and passord field
final String email = etEmail.getText().toString();
final String password = etPassword.getText().toString();
// Initialize AsyncLogin() class with email and password
new AsyncLogin().execute(email, password);
//NYT
}
});
}
private class AsyncLogin extends AsyncTask<String, String, String> {
ProgressDialog pdLoading = new ProgressDialog(LoginActivity.this);
HttpURLConnection conn;
URL url = null;
@Override
protected void onPreExecute() {
super.onPreExecute();
//this method will be running on UI thread
pdLoading.setMessage("\tLoading...");
pdLoading.setCancelable(false);
pdLoading.show();
}
@Override
protected String doInBackground(String... params) {
try {
// Enter URL address where your php file resides
url = new URL("http://192.168.87.100/DUFT/login.inc.php");
} catch (MalformedURLException e) {
// TODO Auto-generated catch block
e.printStackTrace();
return "exception";
}
try {
// Setup HttpURLConnection class to send and receive data from php and mysql
conn = (HttpURLConnection) url.openConnection();
//conn.setReadTimeout(READ_TIMEOUT);
//conn.setConnectTimeout(CONNECTION_TIMEOUT);
conn.setRequestMethod("POST");
// setDoInput and setDoOutput method depict handling of both send and receive
conn.setDoInput(true);
conn.setDoOutput(true);
// Append parameters to URL
Uri.Builder builder = new Uri.Builder()
.appendQueryParameter("username", params[0])
.appendQueryParameter("password", params[1]);
String query = builder.build().getEncodedQuery();
// Open connection for sending data
OutputStream os = conn.getOutputStream();
BufferedWriter writer = new BufferedWriter(
new OutputStreamWriter(os, "UTF-8"));
writer.write(query);
writer.flush();
writer.close();
os.close();
conn.connect();
} catch (IOException e1) {
// TODO Auto-generated catch block
e1.printStackTrace();
return "exception";
}
try {
int response_code = conn.getResponseCode();
// Check if successful connection made
if (response_code == HttpURLConnection.HTTP_OK) {
// Read data sent from server
InputStream input = conn.getInputStream();
BufferedReader reader = new BufferedReader(new InputStreamReader(input));
StringBuilder result = new StringBuilder();
String line;
while ((line = reader.readLine()) != null) {
result.append(line);
}
// Pass data to onPostExecute method
return (result.toString());
} else {
return ("unsuccessful");
}
} catch (IOException e) {
e.printStackTrace();
return "exception";
} finally {
conn.disconnect();
}
}
@Override
protected void onPostExecute(String result) {
//this method will be running on UI thread
pdLoading.dismiss();
if (result.equalsIgnoreCase("true")) {
/* Here launching another activity when login successful. If you persist login state
use sharedPreferences of Android. and logout button to clear sharedPreferences.
*/
Intent intent = new Intent(LoginActivity.this, MenuScreen.class);
startActivity(intent);
LoginActivity.this.finish();
} else if (result.equalsIgnoreCase("false")) {
// If username and password does not match display a error message
//Toast.makeText(LoginActivity.this, "Invalid email or password", Toast.LENGTH_LONG).Show();
} else if (result.equalsIgnoreCase("exception") || result.equalsIgnoreCase("unsuccessful")) {
//Toast.makeText(LoginActivity.this, "OOPs! Something went wrong. Connection Problem.", Toast.LENGTH_LONG).Show();
}
}
}}
我已經按照教程中的所有步驟進行操作,並且可以通過在移動瀏覽器中輸入IPv4地址來使用手機訪問本地服務器。 這必須表示我也能夠訪問此本地服務器上的數據庫,對嗎?
我找到了解決方案! 問題出在這行代碼中
php $servername = "localhost:80";
在這里,我為Apache而不是MySQL定義了端口3307。因此,我將其更改為正確的端口3307 :)
謝謝您的幫助!
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.