在Laravel查詢構建器中運行“存在”查詢

Question

我正在嘗試執行此操作：

SELECT * FROM `lms_test` 
WHERE NOT EXISTS 
   (SELECT * FROM `lms_studenttest` 
    WHERE `lms_test`.slug = `lms_studenttest`.testId 
    AND `lms_studenttest`.`studentId`='10a75c804b8851520993dedc42334c0f'
    ) 
AND `lms_test`.`testType`= 'Practice Test'

但是沒有成功。
幫我做。

Answer 1

我認為您可以嘗試以下示例：

A::whereNotExists(function($query){
  $query->select(DB::raw(1))
        ->from('B')
        ->whereRaw('A.id = B.id');
  })
 ->get();

要么

DB::table('lms_test')
        ->whereNotExists(function ($query) {
            $query->select('lms_studenttest.*')
                  ->from('lms_studenttest')
                  ->where('lms_test.testType', 'Practice Test')
                  ->where('lms_studenttest.studentId', '10a75c804b8851520993dedc42334c0f')
                  ->whereRaw('lms_studenttest.testId = lms_test.slug');
        })
        ->get();

希望對您有幫助！

Answer 2

嘗試：

DB::table('lms_test')
        ->whereNotExists(function ($query) {
            $query->select(DB::raw(1))
                  ->from('lms_studenttest')
                  ->where('lms_test.testType', 'Practice Test')
                  ->where('lms_studenttest.studentId', '10a75c804b8851520993dedc42334c0f')
                  ->whereRaw('lms_studenttest.testId = lms_test.slug');
        })
        ->where('testType','Practice Test')
        ->get();

Answer 3

試試看（我不檢查真實數據，我只寫邏輯）：

SELECT *
    FROM `lms_test` 
    LEFT OUTER JOIN `lms_studenttest`
        ON `lms_test`.slug = lms_studenttest`.testId 
        WHERE `lms_studenttest`.testId IS NULL
        AND `lms_studenttest`.`studentId`='10a75c804b8851520993dedc42334c0f'
        AND `lms_test`.`testType`= 'Practice Test'

Answer 4

嘗試以下條件查詢，讓我知道它是否有幫助：

if (User::where('email', '=', Input::get('email'))->exists()) {
  // user found
}