[英]Best way to split a string in python with multiple separators - while keeping the separators
[英]Split string with multiple separators from an array (Python)
給定一系列分隔符:
columns = ["Name:", "ID:", "Date:", "Building:", "Room:", "Notes:"]
和一些字符串,其中一些列留空(並有隨機的空格):
input = "Name: JohnID:123:45Date: 8/2/17Building:Room:Notes: i love notes"
我怎么能得到這個:
["John", "123:45", "8/2/17", "", "", "i love notes"]
我試過簡單地刪除子串,看看我可以從哪里去,但我仍然卡住了
import re
input = re.sub(r'|'.join(map(re.escape, columns)), "", input)
使用列表通過在中間插入(.*)
來生成正則表達式,然后使用strip
來刪除空格:
import re
columns = ["Name:", "ID:", "Date:", "Building:", "Room:", "Notes:"]
s = "Name: JohnID:123:45Date: 8/2/17Building:Room:Notes: i love notes"
result = [x.strip() for x in re.match("".join(map("{}(.*)".format,columns)),s).groups()]
print(result)
收益率:
['John', '123:45', '8/2/17', '', '', 'i love notes']
strip
部分可以通過正則表達式處理,代價是更復雜的正則表達式,但更簡單的整體表達式:
result = re.match("".join(map("{}\s*(.*)\s*".format,columns)),s).groups()
更復雜:如果字段數據包含正則表達式特殊字符,我們必須轉義它們(這里不是這種情況):
result = re.match("".join(["{}\s*(.*)\s*".format(re.escape(x)) for x in columns]),s).groups()
>>> import re
>>> columns = ["Name:", "ID:", "Date:", "Building:", "Room:", "Notes:"]
>>> i = "Name: JohnID:123:45Date: 8/2/17Building:Room:Notes: i love notes"
>>> re.split('|'.join(map(re.escape, columns)), i)
['', ' John', '123:45', ' 8/2/17', '', '', ' i love notes']
為了擺脫空白,也分裂在空白上:
>>> re.split(r'\s*' + (r'\s*|\s*'.join(map(re.escape, columns))) + r'\s*', i.strip())
['', 'John', '123:45', '8/2/17', '', '', ' i love notes']
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