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[英]Upload files to Amazon S3 with Delphi using temporary security credentials
[英]Upload files to Amazon S3 with Delphi
使用我在另一個主題中找到的代碼。 我在驗證時總是遇到簽名不匹配,盡管 accessKeyID 和 secretAccessKey 被驗證正確。 此外,存儲端點對於存儲桶也是正確的。 使用 Delphi 10 西雅圖。 可能是 CloudComponents 的區域或(本地)時間有問題?
Function Amazon_Upload (fileName, bucket, accessKeyID, secretAccessKey : String) : TCallResult;
var
Service: TAmazonStorageService;
ConAmazon: TAmazonConnectionInfo;
info : TCloudResponseInfo;
upload_stream : TFileStream;
bytes : TBytes;
begin
// create file
upload_stream := TFileStream.Create(fileName,fmOpenRead);
try
// filestream to tBytes
upload_stream.Position := 0;
SetLength(bytes, upload_stream.Size);
upload_stream.Write(bytes[0], upload_stream.Size);
ConAmazon := TAmazonConnectionInfo.Create(nil);
try
// amazon connection parameters
ConAmazon.AccountKey := secretAccessKey;
ConAmazon.AccountName := accessKeyID;
ConAmazon.QueueEndpoint := 'queue.amazonaws.com';
ConAmazon.StorageEndpoint := 's3-eu-central-1.amazonaws.com';
ConAmazon.TableEndpoint := 'sdb.amazonaws.com';
ConAmazon.UseDefaultEndpoints := False;
// storage objects
info := TCloudResponseInfo.Create;
Service := TAmazonStorageService.Create(ConAmazon);
try
// upload document to storage
Service.UploadObject(Bucket, fileName, bytes, TRUE, nil, nil, amzbaPrivate, info);
// get results
Result.Callstatus := info.StatusCode;
Result.Success := info.StatusCode in [Ord(rrOK),ord(rrCreated),ord(rrNoContent)];
Result.Response := TJSONObject.ParseJSONValue(info.StatusMessage);
If Assigned(OnLog) Then
FOnlog(info.StatusCode, ConAmazon.StorageEndpoint + #13#10 + bucket + #13#10 + accessKeyID + #13#10 + secretAccessKey, info.StatusMessage, '');
finally
info.Free;
Service.Free;
end;
finally
ConAmazon.Free;
end;
finally
upload_stream.Free;
end;
end;
我稍微修改了您的代碼,以使用 TBytesStream 而不是 TFileStream 來設置 TBytes 緩沖區上的文件內容。 但大多數情況下,您必須讀取流,而不是寫入流。
現在它不會破壞其內容。
Function Amazon_Upload (fileName, bucket, accessKeyID, secretAccessKey: String) : TCallResult;
var
Service: TAmazonStorageService;
ConAmazon: TAmazonConnectionInfo;
info : TCloudResponseInfo;
upload_stream : TBytesStream;
bytes : TBytes;
begin
// create file
upload_stream := TBytesStream.Create;
upload_stream.LoadFromFile(filename);
try
// filestream to tBytes
upload_stream.Position := 0;
SetLength(bytes, upload_stream.Size);
upload_stream.ReadBuffer(bytes, upload_stream.Size);
ConAmazon := TAmazonConnectionInfo.Create(nil);
try
// amazon connection parameters
ConAmazon.AccountKey := secretAccessKey;
ConAmazon.AccountName := accessKeyID;
ConAmazon.QueueEndpoint := 'queue.amazonaws.com';
ConAmazon.StorageEndpoint := 's3-eu-central-1.amazonaws.com';
ConAmazon.TableEndpoint := 'sdb.amazonaws.com';
ConAmazon.UseDefaultEndpoints := False;
// storage objects
info := TCloudResponseInfo.Create;
Service := TAmazonStorageService.Create(ConAmazon);
try
// upload document to storage
Service.UploadObject(Bucket, ExtractFileName(fileName), bytes, TRUE, nil, nil, amzbaPrivate, info);
// get results
Result.Callstatus := info.StatusCode;
Result.Success := info.StatusCode in [Ord(rrOK),ord(rrCreated),ord(rrNoContent)];
Result.Response := TJSONObject.ParseJSONValue(info.StatusMessage);
If Assigned(OnLog) Then
FOnlog(info.StatusCode, ConAmazon.StorageEndpoint + #13#10 + bucket + #13#10 + accessKeyID + #13#10 + secretAccessKey, info.StatusMessage, '');
finally
info.Free;
Service.Free;
end;
finally
ConAmazon.Free;
end;
finally
upload_stream.Free;
end;
end;
運行你的代碼我發現了問題。 只需更改此行:
Service.UploadObject(Bucket, fileName, bytes, TRUE, nil, nil, amzbaPrivate, info);
通過這一行:
Service.UploadObject(Bucket, ExtractFileName(fileName), bytes, TRUE, nil, nil, amzbaPrivate, info);
您的文件的本地路徑不能出現在遠程調用中(我猜它會混淆服務器,認為您正在嘗試訪問您沒有權限的資源)。
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