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[英]how to pass table row values to next page in input text field after clicking submit button
[英]How to keep the current input after clicking submit button in Laravel filter?
我試圖在laravel過濾器中使用get方法點擊提交按鈕后獲取舊輸入? 在我的視線中
{!! Form::open(['url'=>'/jobseekers','method'=>'GET', 'class'=>'form', 'id'=>'search_data']) !!} <div class="form-group col-md-4"> <input type="text" name="fullname" placeholder="Name" value="{{ Session::get('fullname') }}" class="form-control"/> </div> <div class="form-group col-md-4"><button class="btn btn-flat btn-primary">Search</button> </div>{!! Form::close() !!}
在我的控制器中
$result = null;
if(count($request->all())!=0){
if ($request->has('sub_search')) {
$jobseekers = Jobseeker::Subsearch($request)->paginate(10);
dd($applicant_information);
}else{
$result=Jobseeker::Search($request)->paginate(10);
// dd($orders);
}
}
else{
$jobseekers = Jobseeker::with('calllogs')->orderBy('jobseekers.created_at','DESC')->paginate(16);
}
return view('backend.jobseekers.index',compact('jobseekers','result'));
單擊提交按鈕后,無法在視圖文件中獲取舊的輸入值。請指導我,該怎么做?
<input type="text" name="fullname" placeholder="Name" value="{{ request()->input('fullname') }}" class="form-control"/>
您可以使用非常簡單的Laravel helper函數,它是old("fullname")
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