[英]load data infile in php not work
我嘗試使用加載數據infile在php中制作上傳菜單,導致我需要上傳的文件太大
這是代碼
<html>
<head>
</head>
<body>
<?php
include ("Connections/connection.php");
if (isset($_POST["importodp"])) {
if (!empty($_FILES["excelFile"]["tmp_name"])) {
$filename = explode(".", $_FILES["excelFile"]["name"]);
if ($filename[1] == "csv") {
$file = addslashes($_FILES['excelFile']['tmp_name']);
echo $file;
mysqli_select_db($config, $database_config);
$input_odp = "LOAD DATA LOCAL INFILE '$file' INTO TABLE `odp_report` FIELDS TERMINATED BY ';' OPTIONALLY ENCLOSED BY '\"' ESCAPED BY '\\' LINES TERMINATED BY '\r\n'";
$run_input_odp = mysqli_query($config, $input_odp) or die(mysqli_error());
if (!$run_input_odp) {
echo '<script type="text/javascript">alert("Data cannot uploaded")</script>';
}
if ($run_input_odp) {
echo '<script type="text/javascript">alert("Data successfully uploaded")</script>';
}
} else {
echo 'Chose only csv file';
}
} else {
echo 'Plese Select the file first...!!!';
}
}
?>
<form action="" method="post" enctype="multipart/form-data">
<input type="file" name="excelFile"/>
<input type="submit" name="importodp" value="Import Data from Excel"/>
</form>
</body>
</html>
但是我得到的回報是:
警告:mysqli_error()恰好需要1個參數,第21行給出0
我做錯了嗎?
語法: mysqli_error(connection);
參數: connection
說明: Required. Specifies the MySQL connection to use
Required. Specifies the MySQL connection to use
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