無法從數據庫phpMyAdmin檢索數據

Question

我是一個學習如何設置數據庫和PHP腳本並按照示例進行操作的初學者，然后當我運行login.php腳本時，我無法從數據庫中檢索數據，我真的覺得這是一個非常簡單的問題其他人，但是我試圖解決它，但是沒有成功，所以有人可以看看我的代碼然后改正它嗎？

這是我的PHP腳本：

init.php：

<?php
    $db_name = "webapp";
    $mysql_username = "root";
    $mysql_password = "";
    $server_name = "localhost";
    $con=mysqli_connect($server_name, $mysql_username, $mysql_password, $db_name);

    if (!$con)  {
        echo "Connection Error ......." . mysqli_connect_error();
    } else {
        echo "<h3>Database connection Success .....</h3>";
    }
?>

login.php：

<?php
    require "init.php";
    $user_name = "YASER";
    $user_phone = "123456";

    $sql_query = "select name from user_info where user_name like'$user_name'and
        user_phone like'$user_phone';";

    $result = mysqli_query($con,$sql_query);
    if (mysqli_num_rows($result)>0)
    {
        $row = mysqli_fetch_assoc($result);
        $name = $row["name"];
        echo "<h3> Hello And Wellcome" . $name . "</h3>";
    }  else  {
        echo " No Info Is Available .......";
    }
?>

Answer 1

1st：首先檢查查詢是否正在executing或failing

if(!$result){ echo mysqli_error($con); }

第二：用=代替like

$sql_query = "select name from user_info 
              where user_name='$user_name' and
              user_phone='$user_phone'";

第三：您需要在查詢中提供適當的間距

like'$user_name'and
   ^^^        ^^^ 

至

like '$user_name' and

Answer 2

您的查詢中有錯誤。

試試這個發現錯誤

$result = mysqli_query($con,$sql_query) or die(mysqli_error($con));

您的查詢應如下所示...

'SELECT name FROM user_info WHERE user_name LIKE "'.$user_name.'" AND user_phone LIKE "'.$user_phone.'"';