[英]How can I run this shell script inside python?
我想從python程序運行一個bash腳本。 腳本有這樣的命令:
find . -type d -exec bash -c 'cd "$0" && gunzip -c *.gz | cut -f 3 >> ../mydoc.txt' {} \;
通常我會運行一個子進程調用,如:
subprocess.call('ls | wc -l', shell=True)
但由於引用的跡象,這在那里是不可能的。 有什么建議?
謝謝!
雖然問題已經得到解答,但我仍然會跳進去,因為我假設您要執行該bash腳本,因為您沒有功能相同的Python代碼(基本上比40行更糟糕,見下文)。 為什么這樣做而不是bash腳本?
請記住(作為您的bash腳本)沒有任何錯誤檢查,輸出文件是一個全局變量,但可以輕松更改。
import gzip
import os
# create out output file
outfile = open('/tmp/output.txt', mode='w', encoding='utf-8')
def process_line(line):
"""
get the third column (delimiter is tab char) and write to output file
"""
columns = line.split('\t')
if len(columns) > 3:
outfile.write(columns[3] + '\n')
def process_zipfile(filename):
"""
read zip file content (we assume text) and split into lines for processing
"""
print('Reading {0} ...'.format(filename))
with gzip.open(filename, mode='rb') as f:
lines = f.read().decode('utf-8').split('\n')
for line in lines:
process_line(line.strip())
def process_directory(dirtuple):
"""
loop thru the list of files in that directory and process any .gz file
"""
print('Processing {0} ...'.format(dirtuple[0]))
for filename in dirtuple[2]:
if filename.endswith('.gz'):
process_zipfile(os.path.join(dirtuple[0], filename))
# walk the directory tree from current directory downward
for dirtuple in os.walk('.'):
process_directory(dirtuple)
outfile.close()
用\\
逃避'
標記'
。
即對於每一個: '
,替換為: \\'
三重引號或三重雙引號('''some string'''或“”“其他字符串”“”)也很方便。 看到這里 (是的,它的python3文檔,但它在python2中100%工作)
mystring = """how many 'cakes' can you "deliver"?"""
print(mystring)
how many 'cakes' can you "deliver"?
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