如何在SQL Server中使用命名空間獲取XML節點值？

Question

我必須獲取公司節點元素的值。我嘗試了所有方法來從節點獲取數據，但沒有運氣。 下面是我的XML。

<?xml version="1.0"?>
    <CompanyInvoice xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
      <Customer xmlns="http://t.service/CompanyServices/">
        <Company>
          <CompanyId>10001</CompanyId>
          <CoastalId>454564564564564564564564565465454546565555555</CoastalId>
          <CompanyFederalId>345345</CompanyFederalId>
          <CompanyName>Anytime Home</CompanyName>
          <CompanyAddress>Address1</CompanyAddress>
          <CompanyCity>TR</CompanyCity>
          <CompanyState>UT</CompanyState>
          <CompanyPostalCode>11</CompanyPostalCode>
          <CompanyCountry>IT</CompanyCountry>
          <CompanyTelephone>(999) 999-9999</CompanyTelephone>
        </Company>
        <CustomerId>33642</CustomerId>    
      </Customer>
      </CompanyInvoice>

TSQL代碼：我只是嘗試過此操作，但未獲得任何更新

Declare @DATAXML xml ='<?xml version="1.0"?>
    <CompanyInvoice xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
      <Customer xmlns="http://t.service/CompanyServices/">
        <Company>
          <CompanyId>10001</CompanyId>
          <CoastalId>454564564564564564564564565465454546565555555</CoastalId>
          <CompanyFederalId>345345</CompanyFederalId>
          <CompanyName>Anytime Home</CompanyName>
          <CompanyAddress>Address1</CompanyAddress>
          <CompanyCity>TR</CompanyCity>
          <CompanyState>UT</CompanyState>
          <CompanyPostalCode>11</CompanyPostalCode>
          <CompanyCountry>IT</CompanyCountry>
          <CompanyTelephone>(999) 999-9999</CompanyTelephone>
        </Company>
        <CustomerId>33642</CustomerId>    
      </Customer>
      </CompanyInvoice>'


;WITH XMLNAMESPACES('http://t.service/CompanyServices/' as x)
Select
a.value('x:CompanyId[1]','nvarchar(50)') as CompanyId, 
a.value('x:CoastalId[1]','nvarchar(500)') as CoastalId, 
a.value('x:CompanyName[1]','nvarchar(500)') as CompanyName
From @DATAXML.nodes('/CompanyInvoice/Customer/Company')as a (a)

Answer 1

基本上，您有兩個選擇。 1.正確介紹和使用名稱空間。 注意名稱空間范圍。 2.使用通配符名稱空間（在生產中不建議使用）

Declare @DATAXML xml = N'<?xml version="1.0"?>
    <CompanyInvoice xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
      <Customer xmlns="http://t.service/CompanyServices/">
        <Company>
          <CompanyId>10001</CompanyId>
          <CoastalId>454564564564564564564564565465454546565555555</CoastalId>
          <CompanyFederalId>345345</CompanyFederalId>
          <CompanyName>Anytime Home</CompanyName>
          <CompanyAddress>Address1</CompanyAddress>
          <CompanyCity>TR</CompanyCity>
          <CompanyState>UT</CompanyState>
          <CompanyPostalCode>11</CompanyPostalCode>
          <CompanyCountry>IT</CompanyCountry>
          <CompanyTelephone>(999) 999-9999</CompanyTelephone>
        </Company>
        <CustomerId>33642</CustomerId>    
      </Customer>
      </CompanyInvoice>';


WITH XMLNAMESPACES('http://t.service/CompanyServices/' as x)
Select
a.value('x:CompanyId[1]','nvarchar(50)') as CompanyId, 
a.value('x:CoastalId[1]','nvarchar(500)') as CoastalId, 
a.value('x:CompanyName[1]','nvarchar(500)') as CompanyName
From @DATAXML.nodes('CompanyInvoice/x:Customer/x:Company')as a (a);

-- 

select t.node.value('*:CompanyId[1]', 'int')
from @DATAXML.nodes('*:CompanyInvoice/*:Customer/*:Company') t(node);

Answer 2

試試這個這只是另一個例子

REFERThis以獲取更多信息

  DECLARE @foo XML

SELECT @foo = N'
<harrys>
    <harry>
        <fish>0.015000000000</fish>
        <bicycle>2008-10-31T00:00:00+01:00</bicycle>
        <foo>ü</foo>
    </harry>
    <harry>
        <fish>0.025000000000</fish>
        <bicycle>2008-08-31T00:00:00+01:00</bicycle>
        <foo>ä</foo>
    </harry>
</harrys>
'

SELECT
    CAST(CAST(y.item.query('data(fish)') AS varchar(30)) AS float),
    CAST(LEFT(CAST(y.item.query('data(bicycle)') AS char(25)), 10) AS smalldatetime),
    CAST(y.item.query('data(foo)') AS varchar(25))
FROM
    @foo.nodes('/*') x(item)
    CROSS APPLY
    x.item.nodes('./*') AS y(item)

SELECT
    CAST(CAST(x.item.query('data(fish)') AS varchar(30)) AS float),
    CAST(LEFT(CAST(x.item.query('data(bicycle)') AS char(25)), 10) AS smalldatetime),
    CAST(x.item.query('data(foo)') AS varchar(25))
FROM
    @foo.nodes('harrys/harry') x(item)

SELECT
    CAST(CAST(y.item.query('data(fish)') AS varchar(30)) AS float),
    CAST(LEFT(CAST(y.item.query('data(bicycle)') AS char(25)), 10) AS smalldatetime),
    CAST(y.item.query('data(foo)') AS varchar(25))
FROM
    @foo.nodes('/harrys') x(item)
    CROSS APPLY
    x.item.nodes('./harry') AS y(item)

如果此功能有效，則備用鏈接