[英]Passing a JS variable to PHP Ajax
在變量的這一段中不可能脫穎而出,我嘗試了很多事情……但是,這通常不是一件復雜的事情……
我想將一個變量:SerialNumberJS傳遞給PHP文件(它通過JS(我通過URL:getUrlParameter函數檢索))中! 然后,該變量將在PHP中用於進行基本查詢。 然后回到JS顯示圖表!
請幫助 :)
$(document).ready(function(){
function getUrlParameter(name) {
name = name.replace(/[\[]/, '\\[').replace(/[\]]/, '\\]');
var regex = new RegExp('[\\?&]' + name + '=([^&#]*)');
var results = regex.exec(location.search);
return results === null ? '' : decodeURIComponent(results[1].replace(/\+/g, ' '));
};
var SerialNumberJS = getUrlParameter('SerialNumber');
console.log(SerialNumberJS);
$.ajax({
url : "graphdata.php",
type : "GET",
success : function(data){
console.log(data);
var heure = [];
var payload = [];
for(var i in data) {
heure.push("Heure " + data[i].heure);
payload.push(data[i].payload);
}
var chartdata = {
labels: heure,
datasets: [
{
label: "payload",
fill: false,
lineTension: 0.1,
backgroundColor: "rgba(59, 89, 152, 0.75)",
borderColor: "rgba(59, 89, 152, 1)",
pointHoverBackgroundColor: "rgba(59, 89, 152, 1)",
pointHoverBorderColor: "rgba(59, 89, 152, 1)",
data: payload
}
]
};
var ctx = $("#mycanvas");
var LineGraph = new Chart(ctx, {
type: 'line',
data: chartdata
});
},
error : function(data) {
}
});
});
<?php
//setting header to json
header('Content-Type: application/json');
//database
define('DB_HOST', 'localhost');
define('DB_USERNAME', 'root');
define('DB_PASSWORD', '****');
define('DB_NAME', 'delta');
//get connection
$mysqli = new mysqli(DB_HOST, DB_USERNAME, DB_PASSWORD, DB_NAME);
if(!$mysqli){
die("Connection failed: " . $mysqli->error);
}
$SerialNumber = "00000000010";
//query to get data from the table
$query = 'SELECT heure, payload FROM reception WHERE Serial_number = "'.$SerialNumber.'" ORDER BY date DESC LIMIT 10';
//execute query
$result = $mysqli->query($query);
//loop through the returned data
$data = array();
foreach ($result as $row) {
$data[] = $row;
}
//free memory associated with result
$result->close();
//close connection
$mysqli->close();
//now print the data
print json_encode($data);
?>
要在PHP文件中獲取序列號,您需要在ajax請求的數據元素中傳遞序列號:
$.ajax({
url : "graphdata.php",
type : "GET",
data: {
'SerialNumberJS' : SerialNumberJS // add other if needed
},
success : function(data){
// your code....
}
});
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.