Java Spring Boot-返回json響應

Question

我想為新的Java Spring Boot應用程序創建一個自定義json響應。 目前，我只想創建一個虛擬json對象-開始控制輸出json響應的結構。

當我這樣做時，它想為.puts創建強制轉換前綴-我曾經使用過Mongodb-BasicDBObject-但現在我在這里還沒有mongo。

 DBObject obj = new BasicDBObject();
 obj.put( "foo", "bar" );

我該怎么辦？

-

@RequestMapping(value = "/login", method = RequestMethod.GET)
@CrossOrigin(origins = {"*"})
public ResponseEntity<?> login(
        @RequestParam(value="email", required=false, defaultValue="email") String email,
        @RequestParam(value="password", required=false, defaultValue="password") String password, 
        HttpServletRequest request
        ) throws  Exception {

                Object response = new Object();
                    response.put("information", "test");
                    response.put("id", 3);
                    response.put("name", "course1");

                return new ResponseEntity<>(response, HttpStatus.OK);
        }

Answer 1

**@ResetController**   // add this
public class YourClass{

    @RequestMapping(value = "/login", method = RequestMethod.GET)
    @CrossOrigin(origins = {"*"})
    public ResponseEntity<?> login(){
        Object response = new Object();
                    response.put("information", "test");
                    response.put("id", 3);
                    response.put("name", "course1");

        return new ResponseEntity<>(response, HttpStatus.OK);
     }
}