在char *中間添加一個int（在C中）

Question

想知道如何在char *中間有一個int，如下所示：

char * winning_message =
"Congratulations, you have finished the game with a score of " + INT_HERE +
"                 Press any key to exit...                   ";

Answer 1

也許您正在尋找這樣的東西？

char buf[256];  // make sure this is big enough to hold your entire string!
sprintf(buf, "Congratulations, you have finished the game with a score of %i\nPress any key to exit...", INT_HERE);

請注意，從某種意義上講，以上內容是不安全的，如果您的字符串結尾的長度大於sizeof（buf），則sprintf（）會超出該字符串的末尾寫入並破壞堆棧。 為了避免這種風險，您可以改為調用snprintf（）：

char buf[256];  // make sure this is big enough to hold your entire string!
snprintf(buf, sizeof(buf), "Congratulations, you have finished the game with a score of %i\nPress any key to exit...", INT_HERE);

...唯一的缺點是snprintf（）可能並非在每個操作系統上都可用。

Answer 2

有了這個：

char winning_message[128]; // make sure you have enough space!
sprintf(winning_message, "Congratulations, you have finished the game with a score of %i. Press any key to exit...", INT_HERE);

Answer 3

您可以使用：

char * winning_message;
asprintf(&winning_message,"Congratulations, you have finished the game with a score of %d\nPress any key to exit...\n", INT_HERE);