如何在c中將字符串轉換為十六進制，反之亦然？

Question

如何在c中將字符串轉換為十六進制，反之亦然。 例如：，像“謝謝你”到十六進制格式的字符串：7468616e6b20796f75並且從十六進制7468616e6b20796f75到字符串：“謝謝”。 有沒有辦法做到這一點？

提前致謝

Answer 1

sprintf和sscanf就足夠了。

#include <stdio.h>
#include <string.h>

int main(void) {
  char text[] = "thank you";
  int len = strlen(text);

  char hex[100], string[50];

  // Convert text to hex.
  for (int i = 0, j = 0; i < len; ++i, j += 2)
    sprintf(hex + j, "%02x", text[i] & 0xff);

  printf("'%s' in hex is %s.\n", text, hex);

  // Convert the hex back to a string.
  len = strlen(hex);
  for (int i = 0, j = 0; j < len; ++i, j += 2) {
    int val[1];
    sscanf(hex + j, "%2x", val);
    string[i] = val[0];
    string[i + 1] = '\0';
  }

  printf("%s as a string is '%s'.\n", hex, string);

  return 0;
}

現在

$ ./a.out
'thank you' in hex is 7468616e6b20796f75.
7468616e6b20796f75 as a string is 'thank you'.

Answer 2

要將字符串轉換為十六進制代碼：

#include <stdio.h>
#include <string.h>
#include <stdlib.h>
int main( )
{
    int i;
    char word[] = "KLNCE";
    char hex[20];
    for ( i = 0; i < strlen ( word ); i++ )
    {
        char temp[5];
        sprintf( temp, "%X", word[i] );
        strcat( hex, temp );
    }
    printf( "\nhexcode: %s\n", hex );
    return 0
}

OUTPUT

hexcode: 4B4C4E4345