XmlRpcClient無法分配URL地址

Question

在編譯以下源代碼時出現錯誤：

import java.util.*;
import org.apache.xmlrpc.client.*; 
import org.apache.xmlrpc.common.*;
import org.apache.xmlrpc.*;
public class pms {
    public static void main (String [] args) {
        String UserName = "123";
        String Password = "123";
        String pKey     = "123";
        XmlRpcClient server = new XmlRpcClient("http://localhost/RPC2"); //("http://localhost/RPC2"); 
        Vector params = new Vector();
      try {
         params.addElement(new Integer(17));
         params.addElement(new Integer(13));
         Object result = server.execute("acquire_token",params);
         int sum = ((Integer) result).intValue();
         System.out.println("The sum is: "+ sum);
      } catch (Exception exception) {
         System.err.println("JavaClient: " + exception);
      }
        System.out.println("Hello World");
  }

}

Answer 1

由於我猜沒有XmlRpcClient具有String構造函數，因此出現編譯錯誤，如下所示：

XmlRpcClient中的XmlRpcClient（）不能應用於（java.lang.String）

實際上， XmlRpcClient類僅聲明一個默認的無參數構造函數 ，您應使用該構造函數來創建新實例。

可以使用XmlRpcClientConfigImpl創建服務器URL配置：

import java.util.*;
import org.apache.xmlrpc.client.*; 
import org.apache.xmlrpc.common.*;
import org.apache.xmlrpc.*;

public class pms {
    public static void main (String [] args) {
        String UserName = "123";
        String Password = "123";
        String pKey     = "123";

        // create a configuration instance with the requested URL
        XmlRpcClientConfigImpl config = new XmlRpcClientConfigImpl();
config.setServerURL(new URL("http://localhost/RPC2"));

        // create the client and configure it with instantiated configuration
        XmlRpcClient server = new XmlRpcClient();
        server.setConfig(config);

        Vector params = new Vector();
      try {
         params.addElement(new Integer(17));
         params.addElement(new Integer(13));
         Object result = server.execute("acquire_token",params);
         int sum = ((Integer) result).intValue();
         System.out.println("The sum is: "+ sum);
      } catch (Exception exception) {
         System.err.println("JavaClient: " + exception);
      }
        System.out.println("Hello World");
  }

}

Answer 2

再次錯誤

pms.java:22: error: cannot find symbol
                server.setconfig(config);
                      ^
  symbol:   method setconfig(XmlRpcClientConfigImpl)
  location: variable server of type XmlRpcClient
Note: pms.java uses unchecked or unsafe operations.
Note: Recompile with -Xlint:unchecked for details.

Answer 3

因為我已經檢查並執行了代碼，所以構造函數XmlRpcClient（String str）在JAR xmlrpc-2.0.1版本中可用，之后就將其刪除並添加為具有配置機制的無參數構造函數。

請檢查您使用的是哪個JAR文件。 嘗試使用xmlrpc-2.0.1，它也需要commons-codec-1.13 JAR才能成功運行。

xmlrps-2.0.1 JAR鏈接http://archive.apache.org/dist/ws/xmlrpc/binaries

您可以查看在JDK 1.8上使用提到的JAR版本完成的工作示例

客戶代碼

import java.util.Vector;
import org.apache.xmlrpc.XmlRpcClient;

public class JavaRpcClient {

    public static void main(String[] args) {
        try {
            XmlRpcClient client = new XmlRpcClient("http://localhost:8080/RPC2");
            Vector params = new Vector();

            params.addElement(new Integer(17));
            params.addElement(new Integer(10));

            Object result = client.execute("sample.sum", params);

            int sum = ((Integer) result).intValue();
            System.out.println("The sum is: " + sum);

        } catch (Exception exception) {
            System.err.println("JavaClient: " + exception);
        }
    }
}

服務器代碼

import org.apache.xmlrpc.WebServer;

public class JavaRpcServer {

    public Integer sum(int num1, int num2) {
        return new Integer(num1 + num2);
    }

    public static void main(String[] args) {
        try {
            System.out.println("Attempting to start XML-RPC Server...");

            WebServer server = new WebServer(8080);
            server.addHandler("sample", new JavaRpcServer());
            server.start();

            System.out.println("Started successfully.");
            System.out.println("Accepting requests. (Halt program to stop.)");

        } catch (Exception e) {
        }
    }
}