從文本文件中查找列表中最小的數字：Python

Question

在我的代碼中，我試圖從文本文件中獲取數字列表，並找到其中最小的兩個。 我該怎么辦？

Myfile = open("RoundOneTotalScores.txt","r")

AScore = ()
BScore = ()
CScore = ()
DScore = ()
EScore = ()
FScore = ()

for line in Myfile:
    if "A" in line.split(',')[0]:
        AScore = line.split(',')[1]

for line in Myfile:
    if "B" in line.split(',')[0]:
        BScore = line.split(',')[1]

for line in Myfile:
    if "C" in line.split(',')[0]:
        CScore = line.split(',')[1]

for line in Myfile:
    if "D" in line.split(',')[0]:
        DScore = line.split(',')[1]

for line in Myfile:
    if "E" in line.split(',')[0]:
        EScore = line.split(',')[1]

for line in Myfile:
    if "F" in line.split(',')[0]:
        FScore = line.split(',')[1]


list1 = [AScore, BScore, CScore, DScore, EScore, FScore]

int(list1)
smallest = min(list1)
print(smallest)

Myfile.close()

不斷出現的錯誤是：追溯（最近一次呼叫最近）：EliminateR1（）中文件“”，第1行，EliminateR1中文件“ D：\\ NEA Real \\ Test3.py”，行39 int（list1）TypeError ：int（）參數必須是字符串，類似字節的對象或數字，而不是“列表”

Answer 1

這是一個示例，假設您的數據看起來像這樣。 如果需要最小值，可以使用min 。 如果需要兩個最小值，則可以sort列表進行sort並選擇前兩個值：

txt = """A,1
B,3
F,5
D,4
C,2"""

values = [int(line.split(',')[1]) for line in txt.splitlines()]
print(values)
# [1, 3, 5, 4, 2]
print(min(values))
# 1
print(sorted(values))
# [1, 2, 3, 4, 5]
print(sorted(values)[:2])
# [1, 2]

如果您讀取文件，則可以使用：

with open("RoundOneTotalScores.txt") as f:
    lines = f.readlines()
values = [int(line.split(',')[1]) for line in lines]
print(values)
# [1, 3, 5, 4, 2]
print(min(values))
# 1
print(sorted(values))
# [1, 2, 3, 4, 5]
print(sorted(values)[:2])
# [1, 2]
print(sorted(values)[2:])
# [3, 4, 5]

請注意，定義了諸如list，dict和set之類的集合，因此您無需定義AScore ， BScore ，...