Bash：嵌套的for循環+中間的循環包含兩個數組？

Question

也許我對此考慮過多，但這是我想要的輸出：

one four seven 
one five eight
one six nine
two four seven
two five eight
two six nine
three four seven
three five eight
three six nine

這是我開始的。 我走到第二個for循環，完全迷失了尋找解決方案的念頭。

#!/bin/bash

declare -a aaa=("four" "five" "six")
declare -a bbb=("one" "two" "three")
declare -a ccc=("seven" "eight" "nine")


for bs in ${bbb[@]}; do
  for as in ${aaa[@]}, cs in ${ccc[@]}; do
    echo "$bs" "$as" "$cs"
  done
done

Answer 1

for子句中不能有多個in 。

如果需要同時迭代兩個數組，請遍歷它們的索引：

#! /bin/bash

declare -a aaa=("four" "five" "six")
declare -a bbb=("one" "two" "three")
declare -a ccc=("seven" "eight" "nine")

for b in "${bbb[@]}" ; do
    for i in "${!aaa[@]}" ; do  # or ccc
        echo "$b" "${aaa[i]}" "${ccc[i]}"
    done
done