[英]FirebaseMessagingService is not getting called in AsyncTask's doInBackground
我已推送通知,並且我想在電話收到通知時更新領域對象,但是當我嘗試啟動此對象時:
RealmModelActiveUser actUser= realm.where(RealmModelActiveUser.class).equalTo("id",1).findFirst();
int myid= actUser.getUser().getUser_id();
new ServerBackgroundDownloadConversations(getApplicationContext()) {
@Override
protected void onPostExecute(String result) {
super.onPostExecute(result);
if (!result.equals("Error")) {
Log.i("Conversation", "UPDATED");
}
}
}.execute(myid);
該程序跳入構造函數ServerBackgroundDownloadConversations(getApplicationContext())
但不調用doInBackground,我也不知道為什么。
我的AsyncTask:
public class ServerBackgroundCreateConversation extends AsyncTask<RealmModelConversations,Void,String> {
Context context;
Handler handler;
String out= "";
@SuppressLint("HandlerLeak")
public ServerBackgroundCreateConversation(Context context) {
this.context = context;
handler = new Handler() {
@Override
public void handleMessage(Message msg) {
Bundle bundle= msg.getData();
if (bundle!=null){
out = (String) bundle.get("response");
} else {
out= "Error";
}
}
};
}
@Override
protected String doInBackground(RealmModelConversations... params) {
RealmModelConversations newConv = params[0];
UploadImageApacheHttp uploadTask = new UploadImageApacheHttp();
uploadTask.doFileUpload(newConv.getWork(newConv.getIntWork()), newConv, handler);
while (out.equals("")){
try {
Thread.sleep(50);
} catch (InterruptedException e) {
e.printStackTrace();
}
}
return out;
}
@Override
protected void onPreExecute() {
}
@Override
protected void onPostExecute(String result) {
if (!result.equals("]") || !result.equals("")){
/// prihlási nového user aj do active (login/register)
CreateNewConversation(result);
} else {
result="Error";
}
}
@Override
protected void onProgressUpdate(Void... values) {
super.onProgressUpdate(values);
}
private void CreateNewConversation(String result){
Realm realm= Realm.getDefaultInstance();
try {
Gson gson = new Gson();
Type typeConv = new TypeToken<JsonSablonaConversations>() {
}.getType();
JSONObject pom;
JSONArray parentArray = new JSONArray(result);
JSONObject finalObject = parentArray.getJSONObject(0);
JsonSablonaConversations conversation = gson.fromJson(finalObject.toString(), typeConv);
final RealmModelConversations NewUserConv = new RealmModelConversations();
NewUserConv.setId_dialog(conversation.getId_dialog());
NewUserConv.setDate(conversation.getDate());
NewUserConv.setKey(conversation.getKey());
NewUserConv.setId_user(conversation.getId_user());
NewUserConv.setId_user2(conversation.getId_user2());
NewUserConv.setMeno(conversation.getMeno());
NewUserConv.setMeno2(conversation.getMeno2());
realm.executeTransaction(new Realm.Transaction() {
@Override
public void execute(Realm realm) {
try {
realm.copyToRealmOrUpdate(NewUserConv);
} catch (Exception e) {
int pom=4;
}
RealmResults<RealmModelConversations> ru= realm.where(RealmModelConversations.class).findAll();
}
});
}
catch (Exception e) {
int ppp=4;
ppp++;
}finally {
realm.close();
}
}
}
我嘗試從服務調用的外部線程中調用此↑,但是我的AsyncTask具有處理程序,並且處理程序需要位於runOnUIthread和Thread中。 我無法獲得活動,因為該線程是從無法訪問活動的服務調用的。
我用這段代碼解決了我的問題
public String postData(int myUserId) {
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost("http://www.gallopshop.eu/OFY/getConversations.php");
try {
// Add your data
List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();
nameValuePairs.add(new BasicNameValuePair("id", Integer.toString(myUserId)));
httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
HttpResponse response = httpclient.execute(httppost);
String responseStr = EntityUtils.toString(response.getEntity());
return responseStr;
} catch (ClientProtocolException e) {
// TODO Auto-generated catch block
} catch (IOException e) {
// TODO Auto-generated catch block
}
return null;
}
我將嘗試將此方法和此方法放入簡單的線程中,但是也許不需要,因為它在服務中。
問題-我將其放入Thread還是會影響應用程序的性能?
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