數組中的 p5.js 對象碰撞檢測

Question

所以，這個問題是相似的，但不一樣的這個問題，所以不要標志作為一個重復的問題。 如果我像這樣創建兩個單獨的矩形：

//rec is an object I made for the rectangles
rect1 = new rec(random(width-40), random(height-40), 40, 40);
rect2 = new rec(random(width-40), random(height-40), 40, 40);

我的代碼工作正常。

但是如果我創建一個這樣的矩形數組：

//r is an array I made and rec is an object I made for the rectangles
for(var i = 0;i < 10;i++) {
    r[i] = new rec(random(width-40), random(height-40), 40, 40); 
}

我不能像這樣調用對象內的任何變量：

console.log(r[1].x); //returns: Uncaught TypeError: Cannot read property 'x' of undefined

所以，這是我在 p5.js 中為對象碰撞編寫的代碼：

var rect1;
var r;
var num;
function setup(){
    r = [];
    num = 2;
    createCanvas(windowWidth,windowHeight- 4);
    for(var i = 0;i < num; i++){

        r = new rec(random(width-40),random(height-40),40,40);

    }

}

function draw(){
    background(40);
    r.show();
    console.log(r[1].x);
    for(var i = 0;i < num; i++)    {
        for(var j = 0;j<num; j++){


            if(r[i].x + r[i].width+r[i].xa >= r[j].x && r[i].y +r[i].height >=r[j].y && r[i].y<=r[j].y +r[j].height && r[i].x + r[i].xa <= r[j].x + r[j].width){
                r[i].xa *= -1;
                r[j].xa *= -1;

            }
            if(r[i].y + r[i].height + r[i].ya>= r[j].y && r[i].x +r[i].width>=r[j].x && r[i].x<=r[j].x + r[j].height && r[i].y + r[i].ya <= r[j].y + r[j].height){
                r[i].ya *= -1;
                r[j].ya *= -1;
            }
        }    
    }


}
function rec(x,y,wid,hei){
    this.x = x;
    console.log(this.x);
    this.y = y;
    this.width = wid;
    this.height= hei;
    this.xa = random(2,5);
    this.ya = random(2,5);
    this.show = function(){
        this.x;
        this.y;
        fill(255);
        noStroke();
        rect(this.x,this.y,this.width,this.height);
        this.x += this.xa;
        this.y += this.ya;
        if(this.x > width-this.width||this.x <0){
            this.xa *= -1;
            if(this.x > width/2){
                this.x = width-this.width;
            }else{
                this.x = 0;
            }
        }
        if(this.y > height-this.height||this.y <0){
            this.ya *= -1;
            if(this.y > height/2){
                this.y = height-this.height;
            }else{
                this.y = 0;
            }

        }

    }
}
function windowResized(){
    createCanvas(windowWidth,windowHeight- 4);
}

Answer 1

在你的代碼中，你寫：

for(var i = 0;i < num; i++){

    r = new rec(random(width-40),random(height-40),40,40);

}

但你應該有：

for(var i = 0;i < num; i++){

    r[i] = new rec(random(width-40),random(height-40),40,40);

}

此外，在draw() ：

  r.show();

需要是：

  r[1].show();

或類似。

添加：

r[0].show();

你可以看到你的代碼正常工作！ 只需要添加其余的矩形...

這是演示：

 var rect1; var r; var num; function setup() { r = []; num = 2; createCanvas(windowWidth, windowHeight - 4); for (var i = 0; i < num; i++) { r[i] = new rec(random(width - 40), random(height - 40), 40, 40); } } function draw() { background(40); r[0].show(); r[1].show(); for (var i = 0; i < num; i++) { for (var j = 0; j < num; j++) { if (r[i].x + r[i].width + r[i].xa >= r[j].x && r[i].y + r[i].height >= r[j].y && r[i].y <= r[j].y + r[j].height && r[i].x + r[i].xa <= r[j].x + r[j].width) { r[i].xa *= -1; r[j].xa *= -1; } if (r[i].y + r[i].height + r[i].ya >= r[j].y && r[i].x + r[i].width >= r[j].x && r[i].x <= r[j].x + r[j].height && r[i].y + r[i].ya <= r[j].y + r[j].height) { r[i].ya *= -1; r[j].ya *= -1; } } } } function rec(x, y, wid, hei) { this.x = x; this.y = y; this.width = wid; this.height = hei; this.xa = random(2, 5); this.ya = random(2, 5); this.show = function() { this.x; this.y; fill(255); noStroke(); rect(this.x, this.y, this.width, this.height); this.x += this.xa; this.y += this.ya; if (this.x > width - this.width || this.x < 0) { this.xa *= -1; if (this.x > width / 2) { this.x = width - this.width; } else { this.x = 0; } } if (this.y > height - this.height || this.y < 0) { this.ya *= -1; if (this.y > height / 2) { this.y = height - this.height; } else { this.y = 0; } } } } function windowResized() { createCanvas(windowWidth, windowHeight - 4); }

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