[英]php - Create a JSON array with objects
我正在嘗試通過PHP以這種格式創建JSON數組:
{
"Commands":[
{
"StopCollection":true
},
{
"Send":false
},
{
"HeartbeatSend":60
}
]
}
我要做的最接近的是:通過使用JSON_FORCE_OBJECT
$commands = array();
$commands['Commands'] = array();
array_push($commands['Commands'],array('StopCollection' => true));
array_push($commands['Commands'],array('Send' => false));
array_push($commands['Commands'],array('HeartbeatSend' => 60));
$jsonCommands = json_encode($commands, JSON_FORCE_OBJECT);
哪個輸出
{
"Commands":{
"0":{
"StopCollection":true
},
"1":{
"Send":false
},
"2":{
"HeartbeatSend":60
}
}
}
並使用(object)
$commands = (object) [
'Commands' => [
'StopCollection' => true,
'Send' => false,
'HeartbeatSend' => 60
]
];
$jsonCommands = json_encode($commands);
哪個輸出
{
"Commands":{
"StopCollection":true,
"Send":false,
"HeartbeatSend":60
}
}
兩者都很接近,但我需要Commands
是沒有鍵的對象數組。 我怎么做?
如果要從$ commands Try中刪除索引,
json_encode( array_values($commands) );
你可以這樣做
$commands = array(
'Commands' => array(
array('StopCollection' => true),
array('Send' => false),
array('HeartbeatSend' => 60)
)
);
$jsonCommands = json_encode($commands);
print_r($jsonCommands);
干得好:
$arr["Commands"] = [
["StopCollection" => true],
["Send" => false],
["HeartbeatSend" => 60],
];
echo json_encode($arr);
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