[英]JNA: Invalid memory access
我編寫了一個小的C庫,該庫從DLL中提取信息(鍵)。
GetKey.h
#pragma once
#include <stdint.h>
#define getKey(x) getKeyL(x)
#define getKey(x,y) getKeyP(x,y)
void __declspec(dllexport) getKeyP(char *path, uint8_t key[]);
void __declspec(dllexport) getKeyL(uint8_t key[]);
GetKey.c
#include "getkey.h"
#include <stdio.h>
#include <string.h>
#include <windows.h>
void __declspec(dllexport) getKeyP(char *path, uint8_t key[])
{
int lib = LoadLibraryA((path != NULL) ? path : "myLib");
((void(*)(void))(lib + 0x1340))();
lib += 0x14020;
for (int i = 0; i < 8; ++i)
{
key[i] = *(uint8_t*)(lib + (i << 4));
}
FreeLibrary(lib);
}
void __declspec(dllexport) getKeyL(uint8_t key[])
{
getKeyP(NULL, key);
}
我的Java綁定如下所示:
public class GetKey
{
private static final GetKeyBinding INSTANCE;
static
{
System.setProperty("jna.library.path", "lib/dll/");
GetKeyBinding lib;
try
{
lib = Native.loadLibrary("x86_64/GetKey.dll", GetKeyBinding.class);
}
catch (UnsatisfiedLinkError e)
{
try
{
lib = Native.loadLibrary("i386/GetKey.dll", GetKeyBinding.class);
}
catch (UnsatisfiedLinkError f)
{
System.err.println("Failed to load library");
lib = null;
}
}
INSTANCE = lib;
}
public static void getKey(byte[] path, byte[] key)
{
INSTANCE.getKeyP(path, key);
}
public static void getKey(byte[] key)
{
INSTANCE.getKeyL(key);
}
private static interface GetKeyBinding extends Library
{
void getKeyP(byte[] path, byte[] key);
void getKeyL(byte[] key);
}
}
每當我調用getKeyP
和getKeyL
時,都會拋出異常,我嘗試將參數類型從byte[]
更改為Pointer
以及ByteBuffer
,並且還嘗試extend
StdCallLibrary
(起初對我來說意義不大) ,但是嘗試它永遠不會受到傷害,可以嗎?)仍然會得到異常……而且我知道代碼是可行的,因為我為此編寫了一個小型測試應用程序:
#include <stdio.h>
#include "GetKey.h"
int main()
{
uint8_t key[8];
getKeyP(NULL, key);
for (int i = 0; i < 8; ++i)
{
printf("%02X ", key[i]);
}
getchar();
return 0;
}
它將完全按照我的期望打印到控制台上...任何幫助都將不勝感激!
編輯:
我像這樣從Java調用我的函數:
byte[] key = new byte[8];
GetKey.getKey(key);
將調試器附加到我的DLL並進行調試后,我發現該異常的原因是在預期的字符串之后傳遞了“垃圾”字符。 我通過更改Java代碼來解決此問題:
public static void getKey(String path, byte[] key)
{
INSTANCE.getKeyP((path + '\0').getBytes(), key);
}
現在它可以按預期工作(-:
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