[英]How to set the list by alphanumerical order?
我有一個包含 10 個子文件夾的文件夾,其命名如下:
Folder1,Folder2,Folder3,... 我想按那個順序操作它們但是當我申請時
lst = os.listdir(dirname)
lst.sort()
輸出如下:
Folder1
Folder10
Folder2
Folder3
Folder4
Folder5
Folder6
Folder7
Folder8
Folder9
這是預期的,為了正確排序,我做了以下事情:
lst = os.listdir(dirname)
lst.sort()
projects = {}
for p in lst:
pInt = re.sub(r"Folder", " ", p)
projects[pInt] = p
print(p)
print projects
得到以下結果:
{' 10': 'Folder10', ' 2': 'Folder2', ' 3': 'Folder3', ' 1': 'Folder1', ' 6': 'Folder6', ' 7': 'Folder7', ' 4': 'Folder4', ' 5': 'Folder5', ' 8': 'Folder8', ' 9': 'Folder9'}
我如何從那里開始正確列出它們,以便我的系統按順序一一訪問它們
您可以使用帶有自定義鍵的sorted
。 默認的一個是字典順序,它不適合您的目的。
>>> data
['Folder1', 'Folder10', 'Folder2', 'Folder3', 'Folder4', 'Folder5', 'Folder6', 'Folder7', 'Folder8', 'Folder9']
>>> sorted(data)
['Folder1', 'Folder10', 'Folder2', 'Folder3', 'Folder4', 'Folder5', 'Folder6', 'Folder7', 'Folder8', 'Folder9']
>>> sorted(data, key= lambda s: int(s.replace('Folder', '')))
['Folder1', 'Folder2', 'Folder3', 'Folder4', 'Folder5', 'Folder6', 'Folder7', 'Folder8', 'Folder9', 'Folder10']
如果不是每個文件夾都被稱為FolderX
,你可以使用這個鍵:
>>> sorted(data, key= lambda s: int(''.join(filter(str.isdigit, s))))
['Folder1', 'Folder2', 'Data3', 'Folder4', 'Folder5', 'Folder6', 'Folder7', 'Folder8', 'Folder9', 'Folder10']
另一種方法是將您的folderX
重命名為folder0X
。 然后Folder02
將在Folder10
之前Folder10
。
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