快速從Firebase存儲中刪除圖像

Question

我有一個功能，可以通過滑動tableView單元格從我的Firebase數據庫中刪除一個對象，但是，我的tableView單元格還包含保存在Firebase存儲中的圖像，我也希望在數據為從數據庫中刪除后，我該怎么做？

刪除代碼：

func tableView(_ tableView: UITableView, commit editingStyle: UITableViewCellEditingStyle, forRowAt indexPath: IndexPath) {
    if editingStyle == .delete {

        let name = food[indexPath.row].name
        let ref = Database.database().reference().child("Recipes")

        ref.queryOrdered(byChild: "Name").queryEqual(toValue: name).observe(.childAdded, with: { (snapshot) in
            //Removes deleted cell from firebase
            snapshot.ref.removeValue(completionBlock: { (error, reference) in
                if error != nil {
                    print("There has been an error: \(error)")
                }
                //Removes deleted cell from array
                food.remove(at: indexPath.row)
                //Removes deleted cell from tableView
                tableView.deleteRows(at: [indexPath], with: .left)
            })
        })
    }
}

加載代碼：

let parentRef = Database.database().reference().child("Recipes")
    let storage = Storage.storage()

    parentRef.observe(.value, with: { snapshot in

        if ( snapshot.value is NSNull ) {

            // DATA WAS NOT FOUND
            print("– – – Data was not found – – –")

        } else {

            //Clears array so that it does not load duplicates
            food = []

            // DATA WAS FOUND
            for user_child in (snapshot.children) {

                let user_snap = user_child as! DataSnapshot
                let dict = user_snap.value as! [String: String?]

                //Defines variables for labels
                let recipeName = dict["Name"] as? String
                let recipeDescription = dict["Description"] as? String
                let downloadURL = dict["Image"] as? String

                let storageRef = storage.reference(forURL: downloadURL!)

                storageRef.getData(maxSize: 1 * 1024 * 1024) { (data, error) -> Void in

                    let recipeImage = UIImage(data: data!)

                    food.append(Element(name: recipeName!, description: recipeDescription!, image: recipeImage!))
                    self.tableView.reloadData()
                }
            }
        }
    })

如果有人也可以幫助我解決有關該應用程序的其他問題，我也將非常感謝： 將observe .value轉換為.child

編輯：

從firebase加載對象時，我已將URL添加到數組：

food.append(Element(name: recipeName!, description: recipeDescription!, image: recipeImage!, downloadURL: downloadURL!))

這就是我要用來刪除的內容：

let storage = Storage.storage()
let storageRef = storage.reference()
let desertRef = storageRef.child(food[indexPath.row].downloadURL)

//Removes image from storage
desertRef.delete { error in
    if let error = error {
        print(error)
    } else {
        // File deleted successfully
    }
}

我認為找不到圖像，但是...我收到此錯誤：

錯誤域= FIRStorageErrorDomain代碼= -13010“對象https：/firebasestorage.googleapis.com/v0/b/recipe-app-1b76e.appspot.com/o/B74F604B-68FD-45BB-ABDB-150B03E83A2A.png？alt = media＆token = ae2643c4-6479-4dc8-b389-d04caac98392不存在。” UserInfo = {object = https：/firebasestorage.googleapis.com/v0/b/recipe-app-1b76e.appspot.com/o/B74F604B-68FD-45BB-ABDB-150B03E83A2A.png？alt = media＆token = ae2643c4-6479- 4dc8-b389-d04caac98392，bucket = recipe-app-1b76e.appspot.com，ResponseBody = {“ error”：{“ code”：404，“ message”：“未找到。無法刪除對象”}}，

Answer 1

解決了！ 這對我有用：

let storage = Storage.storage()
let url = food[indexPath.row].downloadURL
let storageRef = storage.reference(forURL: url)

//Removes image from storage
storageRef.delete { error in
    if let error = error {
        print(error)
    } else {
        // File deleted successfully
    }
}

Answer 2

根據圖片位置創建參考。

// Create a reference to the file to delete
let imageRef = storageRef.child("image.png")

// Delete the file
imageRef.delete { error in
  if let error = error {
    // Uh-oh, an error occurred!
  } else {
    // File deleted successfully
  }
}

在下面的行之前添加上面的代碼

food.remove(at: indexPath.row)

使用Firebase Cloud Storage存儲/下載/刪除圖像或視頻 ！