[英]Array list to linked list nodes in C
我想知道是否可以在O(1)時間使用鏈表,並找到了上面的鏈接。 我不懂Java,但知道一點C,而不是C ++。 有人可以解釋這個概念的方法嗎? 您將如何編碼數組以指向鏈接列表? 根據我的知識,我認為我了解如何將節點存儲在**數組中,但不確定如何將其連接到也具有相同節點的*列表。
這是一個簡單的例子。
#include<stdio.h>
#include<stdlib.h>
struct node {
int id;
struct node *next;
struct node *prev;
};
struct node *nodearray[100];
static struct node *head = NULL, *tail = NULL;
void insert_node (struct node **node,int id) {
struct node *new = NULL;
new = malloc(sizeof(*new));
new->id = id;
if (head == NULL) {
head = new;
new->prev = NULL;
} else {
tail->next = new;
new->prev = tail;
}
tail = new;
printf("Added [%d] at %p\n", id, new);
new->next = NULL;
*node = new;
}
void delete_node (int id) {
struct node *node_to_del , *prev, *next;
node_to_del = nodearray[id];
if(!node_to_del)
return;
printf("Del %p\n", node_to_del);
if (node_to_del == head) {
head = node_to_del->next;
node_to_del->next->prev = NULL;
} else if (node_to_del == tail) {
tail = node_to_del->prev;
node_to_del->prev->next = NULL;
} else {
prev = node_to_del->prev;
next = node_to_del->next;
prev->next = next;
next->prev = prev;
}
free(node_to_del);
node_to_del = NULL;
nodearray[id] = NULL;
}
struct node* find_node (int id) {
return nodearray[id];
}
void list_node(void) {
struct node *ptr = head;
while(ptr) {
printf("ptr[%d] %p\n", ptr->id, ptr);
ptr = ptr->next;
}
}
int main () {
insert_node(&nodearray[1] ,1);
insert_node(&nodearray[2] ,2);
insert_node(&nodearray[3] ,3);
insert_node(&nodearray[4] ,4);
insert_node(&nodearray[5] ,5);
printf("1 at %p \n", nodearray[1]);
printf("2 at %p \n", nodearray[2]);
printf("3 at %p \n", nodearray[3]);
printf("4 at %p \n", nodearray[4]);
printf("5 at %p \n", nodearray[5]);
delete_node(1);
delete_node(2);
delete_node(4);
list_node();
printf("1 at %p \n", nodearray[1]);
printf("2 at %p \n", nodearray[2]);
printf("3 at %p \n", nodearray[3]);
printf("4 at %p \n", nodearray[4]);
printf("5 at %p \n", nodearray[5]);
printf("node at 5 = %p\n", nodearray[5]);
return;
}
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