如何在單擊按鈕時迅速消除彈出窗口？

Question

我創建了其中有兩個按鈕的彈出窗口。 單擊彈出框內的按鈕時，我想關閉彈出框。

這是我的代碼：FirstViewController：

 @IBAction func bar_button(_ sender: UIBarButtonItem) {

    let vc = storyboard?.instantiateViewController(withIdentifier: "SecondViewController") as!
    SecondViewController
    vc.preferredContentSize = CGSize(width: 200,height:80)
    let navController = UINavigationController(rootViewController: vc)
    navController.modalPresentationStyle = UIModalPresentationStyle.popover

    let popover = navController.popoverPresentationController
    popover?.delegate = self
    popover?.barButtonItem = sender as! UIBarButtonItem
    self.present(navController, animated: true, completion: nil)

}

SecondViewController：

@IBAction func second_button(_ sender: UIButton) {
    //want to dismiss popover when button clicked
      }
@IBAction func second_button(_ sender: UIButton) {
   //want to dismiss popover when button clicked
      }

Answer 1

呼叫

dismiss(animated: true, completion: nil)

在這些方法中，這將消除顯示的彈出框。