[英]Regex to match multiple instances of a string
我正在嘗試從領事輸出中提取一組字符串。 我要做的是刪除所有以開頭的字符串實例
/usr/lib/ocf/resource.d/
輸入字符串
-rwxr-xr-x. 1 root root 971 Sep 22 13:15 /usr/lib/ocf/resource.d/cloud_init_ocf.sh/n-rwxr-xr-x. 1 root root 662 Aug 28 11:25 /usr/lib/ocf/resource.d/credentialmanagercliRestartVM.sh/n-rwxr-xr-x. 1 root root 843 Sep 28 11:13 /usr/lib/ocf/resource.d/jboss_healthcheck.sh
在上面的示例字符串中,將是
/usr/lib/ocf/resource.d/cloud_init_ocf.sh
/usr/lib/ocf/resource.d/credentialmanagercliRestartVM.sh
/usr/lib/ocf/resource.d/jboss_healthcheck.sh
我嘗試過的
我試圖匹配以\\\\b/usr/lib/ocf/resource.d/.*\\\\b
開頭的字符串
我從這里來的
碼
regexChecker("\\b/usr/lib/ocf/resource.d/.*\\b", output);
private ArrayList<String> regexChecker(String regEx, String str2Check) {
final ArrayList<String> result = new ArrayList<>();
Pattern checkRegex = Pattern.compile(regEx);
Matcher regexMatcher = checkRegex.matcher(str2Check);
String regexMatch;
while (regexMatcher.find()) {
if (regexMatcher.group().length() != 0) {
regexMatch = regexMatcher.group();
result.add(regexMatch);
}
}
return result;
}
我認為問題是在每行末尾插入的/n
字符。
嘗試這種方式
import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class Main{
public static void main(String[] args) {
String regex = "(\\/usr\\/lib\\/ocf\\/resource\\.d\\/[a-zA-Z_]*(\\.sh[\\s|]?)?)";
String string = "-rwxr-xr-x. 1 root root 971 Sep 22 13:15 /usr/lib/ocf/resource.d/cloud_init_ocf.sh/n-rwxr-xr-x. 1 root root 662 Aug 28 11:25 /usr/lib/ocf/resource.d/credentialmanagercliRestartVM.sh/n-rwxr-xr-x. 1 root root 843 Sep 28 11:13 /usr/lib/ocf/resource.d/jboss_healthcheck.sh";
Pattern pattern = Pattern.compile(regex);
Matcher matcher = pattern.matcher(string);
int i =1;
while (matcher.find()) {
System.out.println("Group " + i++ + ": " + matcher.group(0));
}
}
}
和輸出是
Group 1: /usr/lib/ocf/resource.d/cloud_init_ocf.sh
Group 2: /usr/lib/ocf/resource.d/credentialmanagercliRestartVM.sh
Group 3: /usr/lib/ocf/resource.d/jboss_healthcheck.sh
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