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[英]Get an java.io.IOException: Server returned HTTP response code: 400 for URL but can access it fine in browser
[英](Java) HTTP GET request keeps getting 400 response code despite the link working perfectly fine in browser
我正在嘗試使用HTTP從Google趨勢獲取JSON響應。 這是我的代碼段:
public class TestClass {
public static void main(String[] args) throws Exception{
String address = "https://trends.google.com/trends/api/explore?hl=en-US&tz=240&req={\"comparisonItem\":[{\"keyword\":\"Miley\",\"geo\":\"US\",\"time\":\"2012-01-01 2014-01-01\"},{\"keyword\":\"Hannah Montana\",\"geo\":\"US\",\"time\":\"2012-01-01 2014-01-01\"}],\"category\":0,\"property\":\"\"}";
URL url = new URL(address);
HttpURLConnection con = (HttpURLConnection) url.openConnection();
con.setRequestMethod("GET");
int responseCode = con.getResponseCode();
System.out.println("URL is "+address);
System.out.println("Response code is " + responseCode); }
}
這是輸出:
URL is https://trends.google.com/trends/api/explore?hl=en-US&tz=240&req={"comparisonItem":[{"keyword":"Miley","geo":"US","time":"2012-01-01 2014-01-01"},{"keyword":"Hannah Montana","geo":"US","time":"2012-01-01 2014-01-01"}],"category":0,"property":""}
Response code is 400
如果我直接在瀏覽器中輸入URL,Google會為我提供一個JSON文件,沒有問題。 但是,如果嘗試使用Java訪問該URL,則會收到錯誤的請求。 我怎么解決這個問題? 提前致謝。
您需要對URL的查詢字符串部分進行URL編碼。 查看此問題/答案以了解實現此目的的一些方法。
我解決了你的問題。 我高高興興地建議基於apache http api的http請求 。
private static final HttpRequest<String> REQUEST =
HttpRequestBuilder.createGet("https://trends.google.com/trends/api/explore", String.class)
.addDefaultRequestParameter("hl", "en-US")
.addDefaultRequestParameter("tz", "240")
.responseDeserializer(ResponseDeserializer.ignorableDeserializer())
.build();
public void send() {
ResponseHandler<String> responseHandler = REQUEST.execute("req", "{\"comparisonItem\":[{\"keyword\":\"Miley\",\"geo\":\"US\",\"time\":\"2012-01-01 2014-01-01\"},{\"keyword\":\"Hannah Montana\",\"geo\":\"US\",\"time\":\"2012-01-01 2014-01-01\"}],\"category\":0,\"property\":\"\"}");
System.out.println(responseHandler.getStatusCode());
responseHandler.ifHasContent(System.out::println);
}
該代碼打印您通過瀏覽器獲得的響應代碼200和響應正文。
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