[英]undefined index in php when I upload an image to database using mysql
[英]how to upload image to database using php, undefined index:images
任何人都可以幫助我在學校的工作,我感到困惑。圖像無法存儲到數據庫。
<form action="doOrder.php" method="post" enctype="multipart/form-data">
Category : T-SHIRT
Choose Size
<label for="sizes"><span>
<input type="radio" name="sizes" value="S" checked="checked"/>S
<input type="radio" name="sizes" value="M" />M
<input type="radio" name="sizes" value="L" />L
<input type="radio" name="sizes" value="XL" />XL
</span>
</label>
Fabric Type
<select name="fabric">
<option value="Cotton Combed">Cotton Combed</option>
<option value="Cotton Carded">Cotton Carded</option>
<option value="Polyester / PE">Polyester / PE</option>
</select>
Total
<input type="number" name="total" min="1" max="100">
<input type="file" name="imageUpload" id="imageUpload">
<input value="Submit" type="submit" name="submit">
</form>
這是doOrder.php
<?php
require_once("connect.php");
$nama_file = $_FILES['images']['name'];
$sizes = $_POST['sizes'];
$fabric = $_POST['fabric'];
$total = $_POST['total'];
move_uploaded_file($_FILES['images']['tmp_name'], "images/".$_FILES['images']['name']);
$simpan = mysql_query("INSERT INTO pesanan(category, sizes, fabric, total,images) VALUES('T-SHIRT','$sizes','$fabric','$total','$nama_file')");
echo "Your add has been submited....";
?>
錯誤是
注意:未定義索引:第4行中的圖像注意:未定義索引:第9行中的圖像注意:未定義索引:第9行中的圖像
關鍵圖像在文件數組中不存在。 imageUpload
是您從html表單傳遞的name屬性。 這就是您所訪問的
$nama_file = $_FILES['imageUpload']['name'];//imageUpload
move_uploaded_file($_FILES['imageUpload']['tmp_name'], "images/".$_FILES['imageUpload']['name']);
另外,請向您的文件上傳模塊添加驗證。 由於是木馬,因此其他有害文件可以輕松上傳
您實際上嘗試訪問名稱為“ images”的表單輸入-它不存在。 在您的表單中,該字段名為“ imageUpload”
所以改變:
$nama_file = $_FILES['images']['name'];
至:
$nama_file = $_FILES['imageUpload']['name'];
確保在中使用輸入字段的名稱:
這是imageUpload
更改此內容: $nama_file = $_FILES['images']['name'];
對此
$nama_file = $_FILES['imageUpload']['name'];
還:
move_uploaded_file($_FILES['image']['tmp_name'], "images/".$_FILES['image']['name']);
至 :
move_uploaded_file($_FILES['imageUpload']['tmp_name'], "images/".$_FILES['imageUpload']['name']);
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