[英]Break statement not storing data, returns only last value input
我在下面的break語句工作得很好。 沒有錯誤。 但是,當我為多個產品輸入多個值時,它僅返回最后輸入的產品的數據。 例如,如果我輸入productNum = 1且numSold = 5,則productNum = 2,則numSold = 5; 它將僅計算productNum = 2的totalSales,並且僅跟蹤返回值numSold =5。它將“忘記” productNum = 1及其numSold的數據。
我希望它存儲numSold1到numSold5的數據,並且還要繼續向totalSales添加值。 任何人都可以為此指出正確的方向嗎?
這是我的銷售計算器:
public class SalesCalculator {
private int productNum, numSold, numSold1, numSold2, numSold3, numSold4, numSold5;
private double price1 = 2.98, price2 = 4.50, price3 = 9.98, price4 = 4.49, price5 = 6.87, totalSales = 0.00;
public int setProductNum(int productNum) {
this.productNum = productNum;
return productNum;
}
public int setNumSold(int numSold) {
this.numSold = numSold;
return numSold;
}
public double calculateSales() {
switch (productNum) {
case 1:
totalSales += (price1 * numSold); // multiplies how much of this product was sold by its price and adds to overall sales
numSold1 += numSold; // tracks how much of this product was sold of this product
break;
case 2:
totalSales += (price2 * numSold);
numSold2 += numSold;
break;
case 3:
totalSales += (price3 * numSold);
numSold3 += numSold;
break;
case 4:
totalSales += (price4 * numSold);
numSold4 += numSold;
break;
case 5:
totalSales += (price5 * numSold);
numSold5 += numSold;
break;
// default just breaks out of loop in case invalid product number entered
default:
break;
}
return totalSales;
}
public double getTotalSales() { return totalSales; }
public int getNumSold1() { return numSold1; }
public int getNumSold2() { return numSold2; }
public int getNumSold3() { return numSold3; }
public int getNumSold4() { return numSold4; }
public int getNumSold5() { return numSold5; }
// get prices, included because i wasn't sure if assignment required them or not
public double getPrice1() { return price1; }
public double getPrice2() { return price2; }
public double getPrice3() { return price3; }
public double getPrice4() { return price4; }
public double getPrice5() { return price5; }
}
輸入內容如下:
public class SalesCalculatorTest {
public static void main(String[] args){
SalesCalculator salesCalculator1 = new SalesCalculator();
Scanner input = new Scanner(System.in);
int calcSales;
do {
System.out.printf("\nPlease enter the product number, then press ENTER.\n");
int productNum = input.nextInt();
salesCalculator1.setProductNum(productNum);
System.out.printf("\nPlease enter the quantity sold, then press ENTER.\n");
int numSold = input.nextInt();
salesCalculator1.setNumSold(numSold);
System.out.printf("\nType -1 to calculate sales. Press ENTER to input more data.\n");
calcSales = input.nextInt();
} while (calcSales != -1);
if (calcSales == -1) {
salesCalculator1.calculateSales();
}
double totalSales = salesCalculator1.getTotalSales();
System.out.printf("\nTotal sales for products sold was $%.2f", totalSales);
int numSold1 = salesCalculator1.getNumSold1();
double price1 = salesCalculator1.getPrice1();
System.out.printf("\n\nProduct 1 sold %d units at $%.2f each", numSold1, price1);
int numSold2 = salesCalculator1.getNumSold2();
double price2 = salesCalculator1.getPrice2();
System.out.printf("\nProduct 2 sold %d units at $%.2f each", numSold2, price2);
int numSold3 = salesCalculator1.getNumSold3();
double price3 = salesCalculator1.getPrice3();
System.out.printf("\nProduct 3 sold %d units at $%.2f each", numSold3, price3);
int numSold4 = salesCalculator1.getNumSold4();
double price4 = salesCalculator1.getPrice4();
System.out.printf("\nProduct 4 sold %d units at $%.2f each", numSold4, price4);
int numSold5 = salesCalculator1.getNumSold5();
double price5 = salesCalculator1.getPrice5();
System.out.printf("\nProduct 5 sold %d units at $%.2f each\n", numSold5, price5);
}
}
根據你設計你的程序的方式,你需要調用calculateSales()
每一對呼叫后setProductNum()
和setNumSold()
因此,以下行需要在do ... while
循環中:
salesCalculator1.calculateSales();
這樣做的原因是, productNum
和numSold
被蓋寫與每對的呼叫到setProductNum()
和setNumSold()
因此,您需要在當前使用這些值。 否則,您將注意到,所有計算將使用最后設置的值,即。 較早的值被“忘記”。
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