[英]Xamarin android get contacts with addresses
如何聯系地址?
var uri = ContactsContract.Contacts.ContentUri;
string[] projection = {
ContactsContract.CommonDataKinds.StructuredPostal.InterfaceConsts.Id,
ContactsContract.CommonDataKinds.StructuredPostal.InterfaceConsts.DisplayName,
ContactsContract.CommonDataKinds.StructuredPostal.FormattedAddress
};
var cursor = Application.Context.ContentResolver.Query(uri, projection, null, null, null);
var contactList = new List<(string id, string name, string address)>();
if (cursor.MoveToFirst())
{
do
{
contactList.Add(
(
cursor.GetString(cursor.GetColumnIndex(projection[0])),
cursor.GetString(cursor.GetColumnIndex(projection[1])),
cursor.GetString(cursor.GetColumnIndex(projection[2]))
)
);
} while (cursor.MoveToNext());
}
當我嘗試此操作時,出現異常提示“ Invalid column data1”,我只想要聯系人列表及其地址
別名FormattedAddress
(或data1
)存在於以下提供者上:
content://com.android.contacts/data/phones
因此,請使用ContactsContract.CommonDataKinds.Phone.ContentUri
:
var uri = ContactsContract.CommonDataKinds.Phone.ContentUri;
string[] projection = {
ContactsContract.CommonDataKinds.StructuredPostal.InterfaceConsts.Id,
ContactsContract.CommonDataKinds.StructuredPostal.InterfaceConsts.DisplayName,
ContactsContract.CommonDataKinds.StructuredPostal.FormattedAddress
};
var cursor = Application.Context.ContentResolver.Query(uri, projection, null, null, null);
var contactList = new List<(string id, string name, string address)>();
while (cursor.MoveToNext())
{
contactList.Add(
(
cursor.GetString(cursor.GetColumnIndex(projection[0])),
cursor.GetString(cursor.GetColumnIndex(projection[1])),
cursor.GetString(cursor.GetColumnIndex(projection[2]))
)
);
}
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