如何使輸入不讀取特定數字

Question

import java.util.Scanner;

public class Main {

    public static void main(String[] args) {
        Scanner scan = new Scanner(System.in);
        System.out.print("Enter number (0 to quit): ");
        //largest to-do
        double largest = scan.nextDouble();
        double count = 0;

        while (largest != 0) {
            double input = scan.nextDouble();
            //max
            if (input > largest) {
                // not zero
                // while (input > largest){
                //
                // }

                largest = input;
                //counter
                count = 0;

            }
            //counter start
            if(input==largest){
                count++;
            }
            if (input == 0) {
                System.out.println("Largest #: " + largest);
                System.out.println("Occurance: " + count);
            }
        }
    }
}

該程序有效！ 但是，我認為它並不完整...就像用戶嘗試輸入

-17 -5 -2 -1 -1 -1 0

它輸出：

Max: 0
Occurrence: 1

雖然：在我看來，我希望它是：

Max: -1
Occurrence: 3 

我將如何在不使用數組的情況下做到這一點？ 我在櫃台上方開始的那部分代碼中就知道了。

提前致謝。

Answer 1

為什么不這樣呢？

import java.util.Scanner;

public class Main {

    public static void main(String[] args) {
        Scanner scan = new Scanner(System.in);

        System.out.print("Enter number (0 to quit): ");

        double largest = 0, nextDouble;
        int count = 0;

        while ((nextDouble = scan.nextDouble()) != 0) {
            if (nextDouble > largest || largest == 0) {
                largest = nextDouble;
                count = 1;
            }
            else if (nextDouble == largest) count++;
        }

        scan.close();

        if (count == 0) {
            System.out.println("No number entered!");
            return;
        }

        System.out.println("Largest #: " + largest);
        System.out.println("Occurance: " + count);

    }
}