[英]Dropwizard Hibernate Unable to locate persister Error
我已經建立了一個 Dropwizard 項目和我的第一個棒球數據 api 端點。 功能表和類名稱是 rangerstats_player / Player。 我嘗試對一個名為 rangerstats_hitter_season_stats 的表執行相同操作,但是在嘗試執行簡單的 GET 時遇到以下錯誤,並且還沒有弄清楚如何修復它或問題是什么
org.hibernate.UnknownEntityTypeException: Unable to locate persister: core.HitterSeasonStats
下面是兩個類/表的代碼,以顯示相似之處,因為我認為模式完全相同,我不知道可能有什么問題。
HitterSeasonStats.java(注釋掉一些字段以嘗試使其工作,以防它們可能是問題)
@Entity
@Table(name = "rangerstats_hitter_season_stats")
public class HitterSeasonStats {
@Id
private long id;
// @Column(name = "player_id")
// private long playerId;
private int g;
private int pa;
private int ab;
//private double avg;
private int h;
private int single;
@Column(name = "double")
private int doubles;
private int triple;
private int hr;
private int rbi;
private int bb;
private int k;
private int hbp;
private int sf;
// private double slg;
// private double obp;
// private double ops;
// private double war;
//@Column(name = "season_year")
//private Date seasonYear;
public long getId() {
return id;
}
}
HitterSeasonStatsDAO.java
public class HitterSeasonStatsDAO extends AbstractDAO<HitterSeasonStats> {
public HitterSeasonStatsDAO(SessionFactory factory) {
super(factory);
}
public Optional<HitterSeasonStats> findById(Long id) {
return Optional.fromNullable(get(id));
}
public List<HitterSeasonStats> findByPlayer(Long playerId) {
Criteria criteria = criteria().add(Restrictions.eq("playerId", playerId));
return list(criteria);
}
public List<HitterSeasonStats> findByPlayerAndYear(Long playerId) {
Criteria criteria = criteria().add(Restrictions.eq("playerId", playerId));
return list(criteria);
}
}
播放器.java
@Entity
@Table(name = "rangerstats_player")
@NamedQueries({
@NamedQuery(name = "core.Player.findAll",
query = "select p from Player p")
})
public class Player {
@Id
private long id;
@Column(name = "first_name")
private String firstName;
@Column(name = "last_name")
private String lastName;
private String position;
private String team;
private String bat;
@Column(name = "throw_hand")
private String throwHand;
private String height;
private int age;
private int weight;
public long getId() {
return id;
}
public String getfirstName() {
return firstName;
}
public String getlastName() {
return lastName;
}
......
}
PlayerDAO.java
public class PlayerDAO extends AbstractDAO<Player> {
public PlayerDAO(SessionFactory factory) {
super(factory);
}
public Optional<Player> findById(Long id) {
return Optional.fromNullable(get(id));
}
public List<Player> findAll() {
return list(namedQuery("core.Player.findAll"));
}
}
表
rangersstats=# \dt
List of relations
Schema | Name | Type | Owner
--------+----------------------------------+-------+---------------
public | rangerstats_hitter_game_record | table | owner
public | rangerstats_hitter_season_stats | table | owner
public | rangerstats_pitcher_game_record | table | owner
public | rangerstats_pitcher_season_stats | table | owner
public | rangerstats_player | table | owner
編輯:
我相信我已經找到了導致問題的原因。 這就是我注冊 HibernateBundle 的方式。 我已經把它們放在一起形成教程,並從它們中獲取了語法。 我看到我只在我的包中使用 Player 類。 我需要找到一種新方法來連接主 Application 類中的數據庫。
private final HibernateBundle<ApiConfig> hibernatePlayerBundle =
new HibernateBundle<ApiConfig>(Player.class) {
@Override
public DataSourceFactory getDataSourceFactory(ApiConfig configuration) {
return configuration.getDataSourceFactory();
}
};
@Override
public void initialize(final Bootstrap<ApiConfig> bootstrap) {
bootstrap.addBundle(hibernatePlayerBundle);
}
@Override
public void run(final ApiConfig configuration, final Environment environment) {
final PlayerDAO playerDAO = new PlayerDAO(hibernatePlayerBundle.getSessionFactory());
final HitterSeasonStatsDAO hitterSeasonStatsDAO = new HitterSeasonStatsDAO(hibernateHitterSeasonStatsBundle.getSessionFactory());
environment.jersey().register(new HitterSeasonStatsResource(hitterSeasonStatsDAO));
environment.jersey().register(new PlayerResource(playerDAO));
}
我試圖用另一個類創建並添加另一個包,但看起來我們只能有一個包
java.lang.IllegalArgumentException: A metric named io.dropwizard.db.ManagedPooledDataSource.hibernate.active already exists
編輯:
我需要將逗號分隔的類列表傳遞給 HibernateBundle 構造函數,問題解決了! :)
為了以后不再出現此類問題,請使用ScanningHibernateBundle
。
ScanningHibernateBundle
將掃描core
包和所有嵌套的子包,並將所有帶有@Entity
注釋的類添加到 Hibernate SessionFactory
。
private final HibernateBundle<ApiConfig> hibernatePlayerBundle =
new ScanningHibernateBundle<ApiConfig>("core") {
@Override
public DataSourceFactory getDataSourceFactory(ApiConfig configuration) {
return configuration.getDataSourceFactory();
}
};
最好使用core.model
包名代替core
。
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