[英]PHP Display Values from Object within an Array Based on Key
我有以下包含對象和數組的數組。 如何僅基於鍵的值獲得每個對象的特定值? 我已經測試過並且該數組正在顯示(請參見下文),但是我無法根據需要隔離“名稱”值。
我嘗試了以下代碼來獲取名稱值:
case 'field_prgm_housing' :
$node = 'field_color';
$tids = field_get_items('node', $node, $key, $node->language);
$terms = taxonomy_term_load_multiple(array(), array('tid' => $tids));
$nameonly = $terms->[0]->name[0];
return = $nameonly;
break;
Colors (Array, 2 elements)
12 (Object) stdClass
tid (String, 2 characters ) 12
vid (String, 1 characters ) 3
name (String, 9 characters ) Blue
description (String, 0 characters )
format (String, 13 characters ) filtered_html
weight (String, 1 characters ) 0
vocabulary_machine_name (String, 15 characters ) colors
rdf_mapping (Array, 5 elements)
path (Array, 1 element)
13 (Object) stdClass
tid (String, 2 characters ) 13
vid (String, 1 characters ) 3
name (String, 8 characters ) Green
description (String, 0 characters )
format (String, 13 characters ) filtered_html
weight (String, 1 characters ) 0
vocabulary_machine_name (String, 15 characters ) colors
rdf_mapping (Array, 5 elements)
path (Array, 1 element)
Try this
$node = 'field_color';
$tids = field_get_items('node', $node, $key, $node->language);
$terms = taxonomy_term_load_multiple(array(), array('tid' => $tids));
//loop all the values and get the require value
$name = array();
foreach($terms as $term){
$name[] = $term->name;
}
return $name;
$terms->[0]
應該是什么意思?
$terms
是一個數組,因此您必須通過指定要獲取的索引來訪問它,例如: $terms[12], $terms[13]
...
該數組的元素是對象,因此當您獲得一個數組時,必須使用“->”運算符來獲取它的字段(或方法)。
所以它必須像:
$nameonly = $terms[12]->name;
$nameonly = $terms[13]->name;
也可以按照@kranthi的建議遍歷所有數組項。
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