如何確定在Android中單擊了哪個動態按鈕？

Question

我在oncreate中創建了一個動態按鈕，我沒有在XML中放置任何按鈕。

LinearLayout table = (LinearLayout)findViewById(R.id.linearlayout);
Button btnAttendance,btnSched;
btnAttendance = new Button(this);
btnSched = new Button(this);
btnAttendance.setOnClickListener(this);
btnSched.setOnClickListener(this);
table.addView(btnAttendance);
        table.addView(btnSched);

//這是我在實現偵聽器時創建的OnClick方法：

@Override
    public void onClick(View arg0) {
        // TODO Auto-generated method stub
        BackgroundWorker fetchRiddles = new BackgroundWorker(DashActivity.this,"retrieveRiddles");
        switch (arg0.getId()) {
        case 1:  // in this case i usually put "R.id.Button1:" but my problem is that my buttons are dynamic
            fetchRiddles.execute("0,"+username);
            break;
        case 2:
            fetchRiddles.execute("1,"+username);
            break;
    }

如何確定使用開關單擊了哪個按鈕？ 我的按鈕是動態創建的，無需在xml內放置任何按鈕。

Answer 1

您可以通過編程方式設置ID：

btnAttendance = new Button(this);
btnAttendance.setId(100);
btnSched = new Button(this);
btnSched.setId(200);

然后比較：

@Override
    public void onClick(View arg0) {
        // TODO Auto-generated method stub
        BackgroundWorker fetchRiddles = new BackgroundWorker(DashActivity.this,"retrieveRiddles");
        switch (arg0.getId()) {
        case 100:  // in this case i usually put "R.id.Button1:" but my problem is that my buttons are dynamic
            fetchRiddles.execute("0,"+username);
            break;
        case 200:
            fetchRiddles.execute("1,"+username);
            break;
    }